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Chapter 4

Detail Quantity Estimate of Building Works

10 teaching hours 12 marks Estimating and Costing (ENCE 351)

4.1 Two room load bearing single-storey building with verandah

The procedure, once, for every building

  1. Read the drawings and list the items of work under sub-heads (§3.6).
  2. Find the wall length by the centre line or long wall – short wall method (Chapter 2). This one length drives most of the estimate.
  3. Take out the quantities item by item into the measurement sheet, working from the bottom of the foundation upward.
  4. Apply the deduction rules of §1.4 for openings.
  5. Analyse the rates (Chapter 6) and abstract the cost (§3.7).

Work bottom-upward and the items come out in a natural order that is hard to forget: excavation → PCC bed → footings → DPC → plinth filling → superstructure masonry → lintels and slab → floor → plaster → doors and windows → finishing.

Typical stepped foundation — each band is a separate item of workPCC bed 0.90 × 0.201st footing 0.70 × 0.502nd footing 0.50 × 0.303rd footing / plinth 0.30 × 0.40G.L.depth 1.00trench width 0.90
The foundation section that every load-bearing building estimate starts from. One centre-line length serves the trench, the PCC bed, both footings and the plinth wall — only the breadth and depth change.

Items for a two-room building with verandah

S.N.ItemLength usedUnit
1Earthwork in excavation in foundationcentre line, breadth of trenchm³
2PCC 1:3:6 bed in foundationsame, breadth of bedm³
3Masonry in foundation and plinth, footing by footingsame, breadth of each footingm³
4DPC at plinth levelcentre line × wall thicknessm²
5Earth filling in plinthinside dimensions × depthm³
6Brickwork in superstructurecentre line × thickness × height, less openingsm³
7RCC in lintels, sunshade, slabfrom the drawingm³
8Reinforcementbar schedulekg
9Doors and windows — frames and shuttersschedulem³ and m²
10Floor finish, plastering inside and outside, paintingareas, less openings by the §1.4 rulem²

The three quantities that are always asked

earthwork in foundation = centre-line length × trench width × depth brickwork in superstructure = centre-line length × wall thickness × height − volume of all openings plinth area = length × breadth to the OUTER face of the walls

Verandah. A verandah is measured with the building but its walls are usually thinner and it is often open on one or more sides, so its length must be taken separately from the main block. Its plinth area is included in full if it is covered; a projected balcony or open terrace is normally taken at 50%.

Doing it fast — the method that saves the most time

A detail estimate is long but it is not hard. Almost all the time is lost re-deriving lengths that never needed re-deriving. Work in this order and the whole question becomes one table.

1. Get the two centre-line lengths first, and never touch them again.

centre line of the LONG side = 0.15 + 4.50 + 0.30 + 3.00 + 0.15 = 8.10 m centre line of the SHORT side = 0.15 + 4.00 + 0.15 = 4.30 m

Half a wall at each end, plus every internal room and every internal wall in between. Write these two numbers in a box at the top of your answer book.

2. Use the ±b rule instead of re-measuring. For an item of breadth b, the long wall is 8.10 + b and the short wall is 4.30 − b. Write the b column down the page first, then fill the two length columns mechanically — no thinking, no drawing:

Itemblong wall = 8.10 + bshort wall = 4.30 − b
Earthwork in trench0.909.003.40
PCC bed0.909.003.40
1st footing0.708.803.60
2nd footing0.508.603.80
3rd footing and plinth0.308.404.00
Superstructure brickwork0.308.404.00

Six items, and you did one subtraction and one addition each. Every length in the sheet below comes out of this table.

3. Check each row with the centre-line method before you multiply. This is the one check worth its time in an examination, because it catches a wrong length before it is multiplied through three columns. The total centre-line length of this building is fixed:

total centre line = 2 × 8.10 + 3 × 4.30 = 29.10 m for an item of breadth b, with 2 junctions, total length = 29.10 − 2 × ( b / 2 ) = 29.10 − b brickwork, b = 0.30 : 29.10 − 0.30 = 28.80 m long wall + short wall : 2 × 8.40 + 3 × 4.00 = 28.80 m ✓ earthwork, b = 0.90 : 29.10 − 0.90 = 28.20 m long wall + short wall : 2 × 9.00 + 3 × 3.40 = 28.20 m ✓

The two methods must agree exactly, for every value of b. If they do not, you have either miscounted the short walls or used the wrong sign in the ±b rule — and you have found out in ten seconds instead of losing the whole item.

4. Take the deductions in one block at the end, not opening by opening as you go. The volume deducted from brickwork for any opening is simply L × wall thickness × H, and the same L and H serve the plastering deduction (twice, for two faces). One row per opening type, multiplied by the number of them.

5. Fixed order of items. Never hunt for what comes next — it is always this, from the ground upwards:

earthwork → PCC bed → footings → DPC → plinth filling → superstructure brickwork → RCC lintels and slab → doors and windows → floor finish → plaster → painting

6. Sanity checks that take five seconds each.

QuantityExpected
Steel in RCC80 to 120 kg per m³ of concrete
Bricks500 per m³ of brickwork
Mortar20 to 25% of the volume of masonry
Internal plaster arearoughly twice the wall area, because both faces are done
Earthworkalways the largest volume on the sheet

The mistakes that cost marks in this question

TrapThe rule
Counting two short wallsThe partition is a short wall too. Here there are three. This is the commonest single mistake in the paper.
Using one length for every itemThe length changes with b. A 0.90 m trench and a 0.30 m wall do not share a length.
Deducting the slab bearingThe bearing of an RCC slab on a wall is never deducted from the brickwork.
Deducting small bearingsBearings up to 500 cm² (0.05 m²) in section are not deducted — a section is an area.
Beam depth in a framed buildingMeasure the beam below the slab: 500 − 125 = 375 mm, or the flange is counted twice.
Forgetting the +1 on barsNumber of bars or stirrups = (span / spacing) + 1.
Plaster deduction bandsUp to 0.5 m² nothing; 0.5 to 3 m² one face; over 3 m² both faces, adding jambs and soffit.
Lintel lengthClear span + 2 bearings, bearing = thickness of the lintel with a minimum of 12 cm — not the clear span.

Worked estimate — a two-roomed load bearing building

§4.1 — plan: two rooms, one partition, three short wallspartitionROOM 14.50 × 4.00ROOM 23.00 × 4.00DDW2W2W1W1W2W2entrance step 3.50AA8.10 centre to centre4.30 c/c4.503.00walls 0.30 thick
The plan the sheet below is measured from. Read three things off it before you write anything: the two centre-line lengths (8.10 and 4.30), the wall thickness (0.30), and the number of short walls — three, because the partition is one of them.
§4.1 — section on A–A: every band is a separate itemPCC 1:3:6 bed 0.90 × 0.201st footing 0.70 × 0.502nd footing 0.50 × 0.303rd footing / plinth 0.30 × 0.40D.P.C. 0.05lintel 0.15opening 2.10 highR.C.C. slab 0.10, 0.50 projectionparapet 0.20 × 0.90G.L.1.00 deep0.45 plinth3.00 wall0.90trench 0.90 wide
The matching section, cut on A–A. Every band you can see is a separate item in the sheet, and the only thing that changes from item to item is the breadth b and the height — the centre-line length is the same for all of them.
Plan. Two rooms, 4.50 × 4.00 m and 3.00 × 4.00 m internal, separated by one partition. All walls 30 cm thick.
Foundation. Trench 90 cm wide and 1.00 m deep · PCC bed 90 cm wide, 20 cm thick · footings 70 cm (50 cm high), 50 cm (30 cm high) and 30 cm (40 cm high) · plinth 45 cm above ground with a 5 cm DPC.
Superstructure. 30 cm walls 3.00 m high · 10 cm RCC 1:2:4 roof slab with a 50 cm projection all round · 15 cm RCC lintels with 150 mm bearing · 20 cm parapet 90 cm high.
Openings. Door D = 1.2 × 2.1 m (2 no.) · window W1 = 2.0 × 1.5 m (2 no.) · window W2 = 1.5 × 1.5 m (4 no.). Frames 100 × 75 mm.
Step. 3.50 m long at the entrance.

Step 1 — the centre-line lengths. Everything below follows from these two numbers, so they are worked out once and once only:

centre-line length of the LONGER side = 0.30/2 + 4.50 + 0.30 + 3.00 + 0.30/2 = 8.10 m centre-line length of the SHORTER side = 0.30/2 + 4.00 + 0.30/2 = 4.30 m then, by the long wall – short wall method, for an item of breadth b : long wall L = 8.10 + b ( centre to centre PLUS one breadth ) short wall L = 4.30 − b ( centre to centre MINUS one breadth )

There are three short walls, not two — the two external end walls and the partition between the rooms. Forgetting the partition is the commonest single mistake in this question.

Length of a lintel. l = clear span + 2 × bearing. Where the bearing is not given, take it as equal to the thickness of the lintel, with a minimum of 12 cm. Here the lintel is 150 mm thick, so the bearing is 150 mm and a 1.20 m door gets a lintel 1.20 + 2(0.15) = 1.50 m long — which is the figure used throughout the sheet below.

Step 2 — the measurement sheet.

Item 1 — Earthwork in excavation in foundation

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Long walls29.000.901.0016.200L = 8.10 + 0.90 (c/c plus one breadth)
Short walls33.400.901.009.180L = 4.30 − 0.90; three walls — two external and one partition
Entrance step13.700.500.100.1853.70 = 3.50 + 2 × 0.10
Total — Earthwork in excavation in foundation25.565m³

Item 2 — PCC 1:3:6 bed in foundation

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Long walls29.000.900.203.240
Short walls33.400.900.201.836
Entrance step13.700.700.100.259
Total — PCC 1:3:6 bed in foundation5.335m³

Item 3 — First class brickwork in foundation and plinth

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
First footing — 70 cm wide, 50 cm high
Long walls28.800.700.506.160L = 8.10 + 0.70
Short walls33.600.700.503.780L = 4.30 − 0.70
Second footing — 50 cm wide, 30 cm high
Long walls28.600.500.302.580L = 8.10 + 0.50
Short walls33.800.500.301.710L = 4.30 − 0.50
Third footing up to plinth — 30 cm wide, 40 cm high
Long walls28.400.300.402.016L = 8.10 + 0.30
Short walls34.000.300.401.4400.40 = 0.45 plinth height − 0.05 DPC
Entrance step
First footing13.500.600.150.315
Second footing13.500.300.150.1575
Total — Brickwork in foundation and plinth18.1585m³

Notice how the length changes for every footing because the breadth changes: the long wall grows and the short wall shrinks by exactly the same amount, so the total length stays 2(8.10) + 3(4.30) throughout. That identity is the arithmetical check on the whole sheet.

Item 4 — 50 mm damp proof course

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Long walls28.400.30—5.040
Short walls34.000.30—3.600
Door openings21.200.30—−0.720no DPC under a door
Total — 50 mm damp proof course7.920m²

Item 5 — First class brickwork in superstructure

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Main walls — 30 cm thick, 3.00 m high
Long walls28.400.303.0015.120
Short walls34.000.303.0010.800
Parapet wall — 20 cm thick, 90 cm high
Long side29.400.200.903.384
Short side25.200.200.901.872
Gross brickwork in superstructure31.176
Deductions for openings and lintels
Door openings D, 1.2 × 2.121.200.302.10−1.512
Window W1, 2.0 × 1.522.000.301.50−1.800
Window W2, 1.5 × 1.541.500.301.50−2.700
Lintel over doors21.500.300.15−0.135150 mm bearing each end
Lintel over W122.300.300.15−0.207
Lintel over W241.800.300.15−0.324
Total — Brickwork in superstructure, 1:4 cement sand mortar24.498m³

Item 6 — RCC 1:2:4 in slab and lintels

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Roof slab, 100 mm19.405.600.105.2649.40 = 8.10 + 0.30 + 2 × 0.50 projection
Lintel over doors21.500.300.150.135
Lintel over W122.300.300.150.207
Lintel over W241.800.300.150.324
Total — RCC 1:2:4, excluding reinforcement5.930m³

Item 7 — Steel reinforcement

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Slab, at 1% of the volume of concrete0.01 × 5.264 × 7850413.224density of steel = 7850 kg/m³
Lintels, at 1.5% of the volume of concrete0.015 × 0.666 × 785078.4215
Total — Steel reinforcement491.6455kg

Where no bar bending schedule is given, reinforcement is taken as a percentage of the volume of concrete — about 1% for a slab, 1.5% for a lintel or beam, 2% for a column and 5% for a footing — converted to weight at the density of steel, 7850 kg/m³. A full bar bending schedule is worked out in §4.2.

Item 8 — Formwork to the slab and lintels

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Slab soffit19.405.60—52.640
Slab vertical edges130.00—0.103.000perimeter 2 (9.40 + 5.60) = 30.00 m
Lintel sides, doors41.50—0.150.900
Lintel soffit, doors21.200.20—0.4800.20 = 0.30 − 0.10 taken by the frame
Lintel sides, W142.30—0.151.380
Lintel soffit, W122.000.20—0.800
Lintel sides, W281.80—0.152.160
Lintel soffit, W241.500.20—1.200
Slab area resting on the long walls28.400.30—−5.040
Slab area resting on the short walls34.000.30—−3.600
Total — Formwork (centering and shuttering)53.920m²

Item 9 — Sal wood in door and window frames

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Doors25.400.100.0750.0815.40 = 1.20 + 2 × 2.10
Window W128.500.100.0750.12758.50 = 2 × 2.0 + 3 × 1.5
Window W249.000.100.0750.2709.00 = 2 × 1.5 + 3 × 1.5
Total — Sal wood in door and window frames0.4785m³

Item 10 — 12 mm cement plaster 1:6

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Internal faces
Room 4.5 × 4.0 — four walls117.00—3.0051.000perimeter 2 (4.5 + 4.0) = 17.00 m
Room 3.0 × 4.0 — four walls114.00—3.0042.000
Ceilings of both rooms14.504.00—18.000
Ceiling of the second room13.004.00—12.000
External faces
Long walls28.70—3.4560.0303.45 = 0.45 plinth + 3.00 storey height
Short walls24.60—3.4531.740
Deductions for openings, both faces
Doors41.20—2.10−10.080
Window W142.00—1.50−12.000
Window W281.50—1.50−18.000
Total — 12 mm cement plaster 1:6174.690m²

Openings over 3 m² are deducted on both faces, which is why each opening appears with twice its number in the deduction rows. A window of 1.5 × 1.5 = 2.25 m² would strictly be deducted on one face only (§1.4); it is deducted on both here because both faces of these walls are plastered and the reveals are then measured separately — state whichever convention you adopt.

Step 3 — abstract of cost. The quantities are carried forward and priced. The rates below are illustrative; in the examination take them from the district rate or from your own rate analysis, and say so.

Abstract of cost

S.N.Description of itemQuantityUnitRate (Rs)Amount (Rs)
1Earthwork in excavation in ordinary soil25.565m³400.0010,226.00
2PCC 1:3:6 in foundation5.335m³9,000.0048,015.00
3First class brickwork in foundation and plinth18.159m³11,000.00199,743.50
450 mm damp proof course7.920m²700.005,544.00
5First class brickwork in superstructure, 1:424.498m³12,500.00306,225.00
6RCC 1:2:4 in slab and lintels5.930m³15,000.0088,950.00
7Steel reinforcement491.646kg120.0058,997.46
8Formwork to slab and lintels53.920m²650.0035,048.00
9Sal wood in door and window frames0.479m³160,000.0076,560.00
1012 mm cement plaster 1:6174.690m²350.0061,141.50
Total cost of works890,450.46
Add: contingencies @ 3%26,713.51
Add: work-charged establishment @ 2%17,809.01
Estimated cost934,972.98

Estimated cost of the building ≈ Rs 934,973, to which must still be added the flooring, painting, door and window shutters, and the provisions for water supply and sanitary work (8–10%) and electrification (8–10%).

Deductions for openings in brickwork. Deduct the full volume of each door and window opening (area of opening × thickness of wall) and the volume of the lintel over it, since the lintel is measured separately as RCC. Do not deduct for lintel bearings up to 0.1 m³, or for openings up to 0.1 m² (§1.4).

Geometry and item sequence after Er. N. P. Dawadi's worked example; every quantity recomputed here from the dimensions.

4.2 Four room frame structured building with reinforcement calculations

A framed building differs from a load-bearing one in what carries the load, and therefore in what is measured:

Load bearingRCC framed
FoundationContinuous strip under every wallIsolated footings under each column, measured by number
Vertical load pathThe wall itselfColumns; the wall is only an infill panel
Wall thicknessThick — 230 to 350 mmThin — often 115 mm partition, 230 mm external
Length usedCentre line of the wallsColumn centres; beams measured clear between columns
Dominant itemMasonryRCC and reinforcement

Order of taking out a framed building

  1. Excavation for each isolated footing — number × length × breadth × depth.
  2. PCC bed, footing pad, and the column pedestal below plinth.
  3. Columns from footing top to slab soffit, then plinth beams, then floor beams.
  4. Slab — area × thickness, deducting large voids only.
  5. Infill brickwork panel by panel, deducting openings.
  6. Reinforcement, from the bar bending schedule.

Reinforcement calculation

This is the part that carries the marks. Steel is measured as the length of each bar in place, converted to weight:

weight per metre w = d² / 162 kg/m ( d in mm ) total weight = (number of bars) × (cutting length of one bar) × w
Bar ø (mm)81012162025
kg per metre0.3950.6170.8881.5802.4693.858

Cutting length is the clear length plus hooks and bends, less the cover:

straight bar : L = clear span − 2 × cover + 2 × hook one hook = 9d (standard 180° hook) bend allowance : 45° bend adds 1d , 90° bend adds 2d crank (bent-up): add 0.42 D per crank , D = clear depth between the bar centres stirrup : L = perimeter of the stirrup + 2 × hook − bend deductions number of bars or stirrups = (clear span / spacing) + 1

Two rules save marks: always add 1 when counting stirrups or bars from a spacing, and remember that binding wire and rolling margin are not measured separately — they are inside the rate.

Worked estimate — a four-roomed framed building

§4.2 — a framed building is measured member by memberslab 125 mm over 10.60 × 10.609 columns 400 × 400 · 12 beams 250 × 500 · 4 rooms5.005.005.005.0010.00 to column centrespad 1.80 × 1.80
The column grid. In a framed building the walls carry nothing, so nothing is measured on a centre line — you count members instead: 9 columns, 12 beams, one slab, 9 footings.
Grid. Four rooms formed by a 3 × 3 grid of columns at 5.00 m centres each way — 9 columns, 10.00 × 10.00 m to column centres.
Footings. Isolated pads 1.80 × 1.80 × 0.45 m on a 2.00 × 2.00 × 0.10 m PCC 1:3:6 bed, in a pit 2.20 × 2.20 × 1.50 m.
Columns 400 × 400 mm, 3.00 m clear, 8–16 mm bars with 8 mm ties at 150 mm c/c. Pedestals 1.05 m high below plinth.
Beams 250 × 500 mm overall, 5.00 m clear span — 12 beams. Slab 125 mm over 10.60 × 10.60 m.

Item 1 — Earthwork and bedding

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Isolated pits92.202.201.5065.340one pit per column
Total — Earthwork in excavation for the footings65.340m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Under each pad92.002.000.103.600
Total — PCC 1:3:6 bed under the footings3.600m³

Item 2 — RCC in the frame

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Footing pads91.801.800.4513.122
Pedestals below plinth90.400.401.051.512
Columns above plinth90.400.403.004.320
Beams125.000.250.3755.625depth below the slab = 0.500 − 0.125
Slab, 125 mm110.6010.600.12514.04510.60 = 10.00 + 2 × 0.30 overhang
Total — RCC 1:1½:3 in the frame38.624m³

The beam depth is measured below the slab, 500 − 125 = 375 mm. Measuring the full 500 mm would count the flange twice, since the slab has already been measured right across the beams. This is the single commonest error in a framed-building estimate.

Item 3 — Formwork

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Sides of the footing pads361.80—0.4529.160
Sides of the pedestals360.40—1.0515.120
Sides of the columns360.40—3.0043.200
Beam sides245.00—0.37545.000
Beam soffits125.000.25—15.000
Slab soffit110.6010.60—112.360
Slab area occupied by the beams125.000.25—−15.000
Total — Formwork244.840m²

Item 4 — Bar bending schedules

Bar bending schedule — one column C1, 400 × 400 mm, 3.00 m high

Barø (mm)No.Cutting length (m)Total length (m)kg/mWeight (kg)Remarks
Main bars, 16 mm1683.6028.801.58045.513.00 clear height + 0.60 lap and bend
Lateral ties, 8 mm8211.1223.520.3959.29n = 3000/150 + 1 = 21 · length = 2(0.32 + 0.32) − bends + 2 × 9d hooks
Total weight of steel54.80kg

Bar bending schedule — one beam B1, 250 × 500 mm, 5.00 m clear span

Barø (mm)No.Cutting length (m)Total length (m)kg/mWeight (kg)Remarks
Bottom straight, 20 mm2025.6511.302.46927.905.00 clear + 2 × 0.23 bearing − 2 × 0.025 cover + 2 × 9d hooks
Bottom bent-up, 20 mm2025.8711.742.46928.99adds 2 × 0.42 D, with D = 0.45 − 0.19 = 0.26 m
Top anchor, 12 mm1225.4610.920.8899.715.00 + 2 × 0.23 bearing
Stirrups, 8 mm8341.3646.240.39518.27n = 5000/150 + 1 = 34 · length = 2(0.20 + 0.45) − bends + 2 × 9d
Total weight of steel84.86kg
steel in ONE column = 54.80 kg steel in ONE beam = 84.86 kg 9 columns = 9 × 54.80 = 493.23 kg 12 beams = 12 × 84.86 = 1018.36 kg ---------- steel in the columns and beams = 1511.59 kg ( the slab and footing steel is added from their own schedules )
CHECK on the order of magnitude volume of RCC in the frame = 38.624 m³ steel in the columns and beams alone = 1511.59 kg = 39.1 kg per m³

Steel in a framed building normally works out to 80–120 kg per m³ of concrete overall, or roughly 4–6 kg per m² of built-up area. The figure above is lower because the slab and footing reinforcement has not yet been added. A result far outside that band means an error in the cutting length or the bar count — check before writing it down.

Bar bending rules after IS 2502; frame arrangement after Dawadi, Beam, slab and pillar.

4.3 Septic tank with soak pit

A septic tank is a watertight settling chamber that treats sewage from a building where no public sewer exists; the effluent then percolates into the ground through a soak pit (soakaway).

Sizing

capacity = number of users × sewage per head per day × detention period + sludge storage sewage ≈ 90–140 litres per head per day detention ≈ 24 hours sludge ≈ 30 litres per head per year of cleaning interval free board ≈ 0.30 m above the liquid level liquid depth ≈ 0.90 m minimum, 2.10 m maximum width ≈ 0.75–1.80 m ( kept narrow to lengthen the travel of the sewage ) length : breadth = 2:1 to 4:1 ( IS ) , 3:1 to 6:1 ( Chakraborti )

The tank is deliberately made long and narrow. The sewage has to travel the length of the tank while it settles, so a squat tank short-circuits and settles badly. That is also why a baffle wall is set about 0.80 m from the inlet — it stops the incoming flow from disturbing the scum.

Worked estimate — septic tank for 25 users, with soak pit

§4.3 — the flow: tank → inspection chamber → soak pitfree board 0.30liquid depth 1.50baffleR.C.C. cover slab 7550 vent + cowlfootstepsfloor sloped 1 in 203.30 internalSEPTIC TANK 3.30 × 1.10INSPECTIONCHAMBER 0.60brickwork 1:6DRY brickworkbrick aggregatecoarse sandremovable coverSOAK PIT1.20 dia × 1.70 deepinlet100 S.W. pipeG.L.
The whole installation is three structures in series, and a question that asks for “a septic tank with soak pit” expects all three to be measured. The baffle wall is plastered on both faces; the scum board is not plastered at all.
25 users · sewage 120 litres per head per day · detention 1 day · sludge 30 litres per head per year, cleaned every 2 years · free board 0.30 m

Step 1 — capacity and internal size

sewage volume = 25 × 120 × 1 / 1000 = 3.00 m³ sludge volume = 25 × 30 × 2 / 1000 = 1.50 m³ -------- required liquid capacity 4.50 m³ adopt an internal size 3.30 m × 1.10 m with a liquid depth of 1.50 m provided = 3.30 × 1.10 × 1.50 = 5.45 m³ > 4.50 m³ ✓ L : B = 3.30 : 1.10 = 3 : 1 within both 2:1–4:1 and 3:1–6:1 ✓ liquid depth 1.50 m between 0.90 and 2.10 m ✓ overall depth = 1.50 liquid + 0.30 free board = 1.80 m

Step 2 — measurement sheet for the tank

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
For the tank, including working space14.101.902.0515.96954.10 = 3.30 + 2 (0.23 wall + 0.17 working space)
Total — Earthwork in excavation15.9695m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Under the base slab13.761.560.100.58656
Total — PCC 1:3:6 levelling course0.58656m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Base slab, 150 mm13.761.560.150.879843.76 = 3.30 + 2 × 0.23 wall thickness
Top slab, 120 mm13.761.560.120.70387
Manhole opening 0.60 × 0.6010.600.600.12−0.0432
Total — RCC 1:2:4 in the base and top slabs1.54051m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Long walls, 230 mm23.760.231.803.11328measured out to out
Short walls, 230 mm21.100.231.800.9108measured in to in
Baffle wall, 115 mm11.100.1151.500.18975set 0.80 m from the inlet
Total — Brick masonry in 1:4 cement sand mortar4.21383m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Internal faces of the walls18.80—1.8015.840internal perimeter 2 (3.30 + 1.10) = 8.80 m
Internal floor13.301.10—3.630
Both faces of the baffle wall21.10—1.503.300
Total — Waterproof cement plaster 1:2 inside, 20 mm thick22.770m²

The internal plaster of a septic tank is specified 20 mm thick in 1:2 cement sand mortar with a waterproofing compound — richer and thicker than ordinary 12 mm plaster, because the tank must stay watertight. No plaster is measured on the scum board.

Step 3 — inspection chamber

An inspection chamber is built between the septic tank and the soak pit so that the effluent line can be opened, inspected and cleared. It is a small covered masonry box with a benched and channelled floor, and it is measured as a separate item:

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Earthwork in excavation11.201.201.051.512
PCC 1:3:6 bed11.061.060.100.11236
Brick masonry walls, 230 mm40.830.230.800.61088mean length round the chamber
RCC 1:2:4 cover slab, 100 mm11.061.060.100.11236
(read row by row — the items go separately to the abstract)2.3476m³

Where the cover slab carries a manhole opening, remember the IS 1200 rule: an opening larger than 0.1 m² is deducted, a smaller one is not. A 0.45 × 0.45 m cover is 0.2025 m² and therefore is deducted.

Step 4 — soak pit

A soak pit 1.50 m in diameter and 2.00 m deep, lined with honeycomb brickwork and filled with graded boulder and gravel: excavation = π/4 × 1.50² × 2.00 = 3.53 m³ honeycomb lining = π × 1.50 × 2.00 = 9.42 m² filter media, say 80% of the volume = 2.83 m³

The soak pit lining is honeycomb brickwork precisely so that effluent can escape through it — and honeycomb brickwork is measured in m², not m³ (§1.2). That is a favourite one-mark question.

Items to be measured

ItemHow measuredUnit
Earthwork in excavationoutside dimensions of the tank plus working space, × depthm³
PCC bed below the base slaboutside plan area × thicknessm³
RCC base slab, walls and top slabfrom the sectionm³
Brick masonry wallscentre line × thickness × heightm³
Baffle wall / partitionseparatelym³
Cement plaster with waterproofing, insideinternal wet area and base, 20 mm in 1:2 mortarm²
Reinforcementbar schedulekg
Inspection chamber between tank and soak pitexcavation, PCC, masonry, cover slab — measured as a separate small structurem³ and no.
Manhole cover and frame, vent pipe, inlet and outlet T-pipescountednumber
Soak pit — excavation, honeycomb lining, boulder and gravel fillingvolume and surface of the pitm³ and m²

Dawadi, RCC T-beam, well, septic, caisson, pier; sizing per the standard septic tank design practice.

4.4 Underground water tank

An underground water tank (reservoir) is estimated exactly like a septic tank but is designed to hold clean water, so the whole shell is watertight RCC and the internal finish matters.

Sizing

capacity (litres) = number of users × demand per head per day × storage days volume (m³) = capacity / 1000 domestic demand ≈ 100–135 litres per head per day storage ≈ 1 day for a house, 2–3 days for an institution free board ≈ 0.15–0.30 m

Remember 1 m³ = 1000 litres. A tank for 20 people at 135 l/head/day for one day needs 2700 litres = 2.7 m³, plus free board.

Worked estimate — RCC underground water tank

§4.4 — RCC underground tank, all walls measured to outside facesmanhole 500top slab 150base slab 150PCC 1:3:6, 100wall 2005.00 internal3.00 deep45.00 m³ providedG.L.
The tank is one closed RCC box. Measure the walls to their outside faces and the slabs over the full outside dimensions, then take the excavation 0.20 m clear of the outside face all round for working space.
Serving 40 persons at 135 litres per head per day with 1 day of storage.
Adopted: internal size 5.00 × 3.00 m, depth 3.00 m · walls 200 mm RCC 1:2:4 · base slab 150 mm · top slab 150 mm · PCC 1:3:6 bed 100 mm · 500 mm iron manhole cover.

Step 1 — check the capacity

required = 40 × 135 × 1 / 1000 = 5.40 m³ provided = 5.00 × 3.00 × 3.00 = 45.00 m³ > 5.40 m³ ✓ ( the surplus provides the free board and a reserve )

Step 2 — the measurement sheet

Item 1 — Earthwork and bedding

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
For the tank15.403.403.2559.6705.40 = 5.00 + 2 × 0.20 · 3.40 = 3.00 + 2 × 0.20 · 3.25 = 3.00 + 0.15 slab + 0.10 PCC
Total — Earthwork in excavation59.670m³
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Under the base slab15.403.400.101.836
Total — PCC 1:3:6 levelling course1.836m³

Item 2 — RCC 1:2:4, excluding reinforcement

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Base slab, 150 mm15.403.400.152.754
Side walls — 200 mm thick, 3.00 m high
Long walls25.400.203.006.480measured out to out
Short walls23.000.203.003.600measured in to in
Top slab cover, 150 mm15.403.400.152.754
Deduction for the 500 mm circular manhole− ( π × 0.50² / 4 ) × 0.15-0.02945
Total — RCC 1:2:4 in the tank15.55855m³

Item 3 — Steel reinforcement

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
At 1% of the volume of RCC0.01 × 15.559 × 78501,221.3460density of steel = 7850 kg/m³
Total — Steel reinforcement1,221.3460kg

Item 4 — Formwork and finishing

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Wall inner faces116.00—3.0048.000internal perimeter 2 (5.00 + 3.00) = 16.00 m
Wall outer faces117.60—3.0052.800external perimeter 2 (5.40 + 3.40) = 17.60 m
Soffit of the top slab15.003.00—15.000
Total — Formwork115.800m²
Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
Internal faces of the walls116.00—3.0048.000
Internal floor15.003.00—15.000
Total — Waterproof cement plaster 1:363.000m²

Item 5 — Fittings

Description of itemNo.L (m)B (m)H / D (m)QuantityRemarks
500 mm dia. iron manhole cover1———1.00number
Iron steps built into the wall6———6.00number
25 mm dia. GI inlet pipe110.00——10.00running metre
20 mm dia. GI outlet pipe15.00——5.00running metre
20 mm dia. overflow pipe12.00——2.00running metre
20 mm dia. drain pipe15.00——5.00running metre

Pipes, valves and fixtures of different sizes are counted or measured in running metre from the drawing, each size as a separate item — they are never lumped together.

Items to be measured

  1. Earthwork in excavation — outside dimensions plus working space, to the full depth; classed by soil, and separately below the water table.
  2. PCC levelling course under the base slab.
  3. RCC base slab, walls and top slab, with the manhole deducted.
  4. Reinforcement from the bar schedule, or as a percentage of the concrete.
  5. Formwork to both faces of the walls and to the soffit of the top slab.
  6. Waterproof cement plaster inside, and plaster outside.
  7. Manhole cover, rungs, vent, inlet, outlet, overflow and washout pipes.
  8. Backfilling in layers around the tank, and disposal of surplus earth.
volume of walls = centre-line perimeter × thickness × height for an internal size L × B and wall thickness t : centre-line perimeter = 2[(L + t) + (B + t)]

Note the difference from a building: for a tank the internal dimensions are fixed by the capacity, so the centre-line perimeter is found by adding one wall thickness to each internal dimension — the mirror image of the crossing method in §2.3.

Geometry after Dawadi, 1 km highway, RCC water tank and building §6.12; every quantity recomputed here from the dimensions.

Sources consulted for this chapter

These are the references actually used in writing this chapter. Where a worked example is taken from one of them, the figure or the sheet is recomputed here from the stated dimensions rather than transcribed.