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Chapter 7

Valuation

4 teaching hours 6 marks Estimating and Costing (ENCE 351)

7.1 Purpose, importance and principle of valuation2067

Past Exam Questions on this Topic

  1. Why valuation of property is required? Differentiate between obsolescence and depreciation. [5] (2067 Ashadh, Q.4(a))
    Solution

    a) Why valuation of property is required

    Purposes of valuation — why it is required

    1. Buying and selling — to fix a fair price for both parties.
    2. Rent fixation — standard rent is normally 6–10% of the value.
    3. Security of a loan / mortgage — a bank lends only a fraction of the valuated amount.
    4. Taxation — property tax, house tax, wealth tax and municipal rates are assessed on value.
    5. Compulsory acquisition by government, to fix the compensation payable.
    6. Insurance — to fix the sum insured and the premium.
    7. Probate, partition and inheritance — to divide property among heirs.
    8. Court cases and arbitration — to settle disputes.
    9. Auction — to fix the upset (reserve) price.
    10. Speculation and investment decisions — to judge whether a purchase is worthwhile.
    11. Betterment charges, when a public work raises the value of adjoining land.

    b) Obsolescence distinguished from depreciation

    DepreciationObsolescence
    CausePhysical — wear and tear, decay, age, weatheringFunctional — the property becomes out of date, out of fashion or unsuitable for present needs
    Depends onThe age and condition of the property itselfChanges outside the property — new design, new technology, changed taste, changed town planning
    RateSlow and steady; can be calculated year by yearSudden and unpredictable; cannot be forecast
    Can it be prevented?Slowed by good maintenance and repairNo — maintenance does not help at all
    ExamplePlaster cracking and timber decaying in a 40-year-old houseA sound old house with no lift, small rooms and no parking, unsaleable beside modern apartments

    A building can be physically sound and still lose most of its value through obsolescence — which is why a valuer must consider both.

    ENCE 351 §7.1 and §7.2.

  2. Define valuation and explain how computer helps in valuation task for engineer. A prospective investor desires to purchase a piece of converted land measuring 1,56,000 sq ft in area. After developing this land for housing colony, he wants to sell the plots (1700 sq ft in area) at the rate of Rs. 9,300 per sq ft which is prevailing in the vicinity and thus earn net profit of 22% in the bargain. With the following information, work out the valuation of the undeveloped property. Express the value of property per sq ft basis.
    • a) Deduction for roads, parks, electric substations = 30% area
    • b) Levelling, dressing and jungle clearance cost = Rs. 5 per sq ft
    • c) Cost of providing roads, drainage, w/s and electric sub-station = Rs. 400 per sq ft
    • d) Engineer’s fee and miscellaneous charges = 5% of sale price
    • e) Legal charges, brokerage and advertisement = 10% on sale price
    [2+6] (CM 2082 Chaitra, Q.13)
    The numerical part of this question applies the development method — see also Section 7.4.
    Solution

    a) Valuation, and how a computer helps the engineer in valuation

    Valuation. The art and science of estimating the fair present value of a property — land, building, factory or other engineering structure — on the basis of its present condition, its income-earning capacity, its future life, and the prevailing market conditions.

    A computer assists the valuer in several practical ways:

    • Spreadsheets compute year's purchase, sinking fund and depreciation instantly, and allow "what-if" analysis — the effect of a change in the interest rate or the life can be seen at once.
    • Databases of sale deeds and rates can be searched for genuinely comparable properties, which is the weakest part of manual valuation.
    • GIS links a plot to its cadastral map, land use zone, road width and surrounding sale prices, and produces value contours for a locality.
    • CAD and quantity take-off software give the plinth area and the replacement cost quickly and accurately.
    • Automated valuation models apply regression to a large body of sale data to produce a mass appraisal for taxation.
    • Report generation is standardised, so no component of the report is omitted, and records are archived and auditable.

    b) Valuation of the undeveloped property — development method

    Area of converted land = 1,56,000 sq ft
    Plots of 1700 sq ft to be sold @ Rs 9,300 per sq ft
    Required net profit = 22%
    a) Deduction for roads, parks, electric sub-stations = 30% of area
    b) Levelling, dressing and jungle clearance = Rs 5 per sq ft
    c) Roads, drainage, water supply, sub-station = Rs 400 per sq ft
    d) Engineer's fee and miscellaneous = 5% of sale price
    e) Legal charges, brokerage and advertisement = 10% of sale price

    Saleable area

    area lost to roads, parks and sub-stations = 30% saleable area = 1,56,000 × (1 − 0.30) = 1,56,000 × 0.70 = 1,09,200 sq ft

    Gross sale price of the developed plots

    sale price = 1,09,200 × Rs 9,300 = Rs 1,01,55,60,000 ( Rs 101.556 crore )

    Deductions from the sale price

    i) developer's profit @ 22% of sale price = 0.22 × 1,01,55,60,000 = Rs 22,34,23,200 ii) engineer's fee and misc. @ 5% = 0.05 × 1,01,55,60,000 = Rs 5,07,78,000 iii) legal, brokerage, advertisement @ 10% = 0.10 × 1,01,55,60,000 = Rs 10,15,56,000 iv) levelling, dressing, jungle clearance = 1,56,000 × Rs 5 = Rs 7,80,000 v) roads, drainage, w/s, sub-station = 1,56,000 × Rs 400 = Rs 6,24,00,000 ------------------ total deductions = Rs 43,89,37,200

    Value of the undeveloped property

    value = gross sale price − total deductions = 1,01,55,60,000 − 43,89,37,200 = Rs 57,66,22,800 value per sq ft = 57,66,22,800 / 1,56,000 = Rs 3,696.30 per sq ft
    Value of the undeveloped property = Rs 57,66,22,800 (≈ Rs 57.66 crore), i.e. Rs 3,696.30 per sq ft. The investor should not pay more than this.

    Three points decide the marks. The development cost is spent on the whole 1,56,000 sq ft but the income comes only from the saleable 1,09,200 sq ft. The profit and the fees are percentages of the sale price, not of the cost. And the answer is expressed per sq ft of the original area, since that is what the investor is buying.

    ENCE 351 §7.1 and §7.4.

    • a) Why valuation is done? Explain different parameters affecting the valuation of the property.
    • b) A building having estimated future life of 80 years, fetches a gross annual rent of Rs. 2500 per month. Work out its capitalized value on the basis of 8% net yield. The land plot of the above building measures 1200 m² and cost of land is taken at Rs. 100 per m². The other outgoings are: Repair and maintenance (1/12)th of gross income; Municipal taxes and property tax 25% of gross income; Management and miscellaneous charges 8% of gross income. The plinth area of the building is 600 m² and plinth area rate of the building is Rs. 200 per m².
    [2+2+6] (CM 2078 Chaitra, Q.11)
    The second half of part a belongs to Section 7.3 and part b to Section 7.4.
    Solution

    a) Why valuation is done, and the parameters affecting the value of a property

    Purposes of valuation — why it is required

    1. Buying and selling — to fix a fair price for both parties.
    2. Rent fixation — standard rent is normally 6–10% of the value.
    3. Security of a loan / mortgage — a bank lends only a fraction of the valuated amount.
    4. Taxation — property tax, house tax, wealth tax and municipal rates are assessed on value.
    5. Compulsory acquisition by government, to fix the compensation payable.
    6. Insurance — to fix the sum insured and the premium.
    7. Probate, partition and inheritance — to divide property among heirs.
    8. Court cases and arbitration — to settle disputes.
    9. Auction — to fix the upset (reserve) price.
    10. Speculation and investment decisions — to judge whether a purchase is worthwhile.
    11. Betterment charges, when a public work raises the value of adjoining land.

    Factors affecting the value of a property

    Physical factors

    • Location — the single most important factor; a central or commercial location commands a far higher value.
    • Size, shape and frontage of the plot; a regular plot with good road frontage is worth more than an irregular one.
    • Type, age and condition of the building, and its remaining useful life.
    • Quality of construction, specification and workmanship.
    • Availability of services — water supply, drainage, electricity, telephone, road access.
    • Soil condition and topography, and liability to flooding or landslide.

    Economic factors

    • Supply and demand for property in that locality.
    • Rental income the property can fetch, and the security of that income.
    • Prevailing rate of interest — a lower rate raises the year's purchase and hence the value.
    • Cost of construction at the present time.
    • Inflation and the general state of the economy.

    Legal and social factors

    • Clear title, freehold or leasehold tenure, and the unexpired lease period.
    • Encumbrances — mortgage, easement, right of way, tenancy.
    • Town planning restrictions — land use zoning, setback, floor area ratio, height limit.
    • Neighbourhood and social environment, proximity to schools, hospitals and markets.
    • Government policy — taxes, rent control, planned public works.

    b) Capitalized value of the building

    Estimated future life = 80 years · gross rent = Rs 2,500 per month · net yield = 8%
    Land = 1,200 m² @ Rs 100 per m²
    Plinth area = 600 m², plinth area rate = Rs 200 per m²
    Outgoings: repair and maintenance 1/12 of gross income; municipal and property tax 25%; management and miscellaneous 8%

    Gross annual income

    gross annual rent = 2,500 × 12 = Rs 30,000

    Outgoings

    repair and maintenance = (1/12) × 30,000 = Rs 2,500 municipal and property tax = 25% of 30,000 = Rs 7,500 management and misc. = 8% of 30,000 = Rs 2,400 ---------- total outgoings = Rs 12,400

    Net annual income

    net income = 30,000 − 12,400 = Rs 17,600

    Year's purchase for 80 years at 8%

    YP = [ 1 − (1 + i)−n ] / i = [ 1 − (1.08)−80 ] / 0.08 (1.08)80 = 471.955 → (1.08)−80 = 0.002119 YP = ( 1 − 0.002119 ) / 0.08 = 0.997881 / 0.08 = 12.4735

    Capitalized value of the building

    capitalized value = net income × YP = 17,600 × 12.4735 = Rs 2,19,533.85

    Add the value of the land

    land = 1,200 m² × Rs 100 = Rs 1,20,000 total value = 2,19,533.85 + 1,20,000 = Rs 3,39,533.85
    Capitalized value of the building = Rs 2,19,533.85; total value of the property including land = Rs 3,39,533.85, say Rs 3,39,534.

    The plinth area data (600 × 200 = Rs 1,20,000) gives the cost of the building. Note that its capitalized value, Rs 2.20 lakh, is nearly twice its cost — a good illustration of the difference between cost and value. Over 80 years the sinking fund instalment on Rs 1,20,000 at 8% is only about Rs 20 a year, so omitting it changes nothing material.

    ENCE 351 §7.1 and §7.4.

    • a) Explain importance of specification and valuation. What are the different methods of working out the valuation of property?
    • b) A RCC framed structure building having estimated future life 80 years, fetches a gross annual rent of Rs. 2220 per month. Work out its capitalized value on the basis of 6% net yield. The rate of compound interest for sinking fund may be taken 4%. The land plot of above building measures 1400 sqm and cost of land may be taken to be Rs. 120 per sqm. The other outgoings are: (i) Repair and maintenance 1/12th of the gross income (ii) Municipal taxes and property tax 25% of gross income (iii) Management and miscellaneous charges 7% of gross income.
    [equal marks] (CM 2074 Magh, Q.8)
    The specification part of a belongs to Chapter 8, the methods part to Section 7.4 and part b to Section 7.4.
    Solution

    a) Importance of specification and of valuation, and the methods of valuation

    Importance of specification. The drawing shows the size of the work; the specification states the quality. Together they define the work completely. A specification is important because it fixes the class of material and workmanship, forms the legal basis of the contract, is essential for the analysis of rates (the rate cannot be worked out until the item is defined), guides the contractor in execution and the engineer in acceptance, prevents disputes, and is the standard against which the work is measured and paid.

    Importance of valuation. Valuation fixes the fair present worth of a property, and is required for sale and purchase, rent fixation, mortgage and bank loans, taxation, compulsory acquisition and compensation, insurance, partition and probate, court cases, and investment decisions.

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    b) Capitalized value of the RCC framed building

    Future life = 80 years · gross rent = Rs 2,220 per month
    Net yield = 6% · sinking fund at 4% compound interest
    Land = 1,400 m² @ Rs 120 per m²
    Outgoings: repair and maintenance 1/12 of gross income; municipal and property tax 25%; management and miscellaneous 7%

    Gross annual income

    gross annual rent = 2,220 × 12 = Rs 26,640

    Outgoings

    repair and maintenance = (1/12) × 26,640 = Rs 2,220.00 municipal and property tax = 25% = Rs 6,660.00 management and misc. = 7% = Rs 1,864.80 ------------- total outgoings = Rs 10,744.80

    Net annual income

    net income = 26,640.00 − 10,744.80 = Rs 15,895.20

    Year's purchase — dual rate, 6% yield with 4% sinking fund

    sinking fund coefficient S = s / [ (1+s)n − 1 ] = 0.04 / [ (1.04)80 − 1 ] (1.04)80 = 23.0498 S = 0.04 / 22.0498 = 0.0018141 YP = 1 / ( i + S ) = 1 / ( 0.06 + 0.0018141 ) = 1 / 0.0618141 = 16.1775

    Capitalized value

    value of building = 15,895.20 × 16.1775 = Rs 2,57,145.32 value of land = 1,400 × 120 = Rs 1,68,000.00 --------------- total value of the property = Rs 4,25,145.32
    Capitalized value of the building = Rs 2,57,145.32; total value of the property including land = Rs 4,25,145.32, say Rs 4,25,145.

    Because a separate sinking fund rate is given, the dual rate year's purchase must be used: the investor earns 6% on his capital but can only reinvest the recoupment instalments safely at 4%. Using YP = 100/6 = 16.67 (perpetuity) would ignore the fact that the building has a finite life.

    ENCE 351 §7.4 and §8.3.

  3. Define value of any property and what is to be satisfied by any property to have its value. A person desires to sell his property having details as: Gross rent = Rs. 5000 per month, total outgoings = 25% of gross rent, estimated future life = 35 yrs, area of land = 200 m², estimated value of land = Rs. 2000 per square meter. Determine the fair value of property. Take rate of interest on capital as 10% and rate of redemption of capital as 5%. Assume suitable data, if required. [1+6] (CM 2073 Bhadra, Q.7)
    The first part also belongs to Section 7.2 and the numerical to Section 7.4.
    Solution

    a) Value of a property, and what a property must satisfy to have value

    Value is the present worth of the benefits that will arise from the ownership of a property — what it is worth today to its owner or in the market. It is not the same as its cost.

    For a property to possess value, four conditions must all be satisfied:

    1. Utility — it must be capable of satisfying some want or need. A thing of no use to anybody has no value.
    2. Scarcity — it must be limited in supply relative to demand. Air is useful but free because it is not scarce.
    3. Transferability — the ownership must be capable of being transferred, with a clear and marketable title free of dispute.
    4. Effective demand — there must be a purchaser who not only wants it but has the means and the willingness to pay for it. Desire without purchasing power creates no value.

    b) Fair value of the property

    Gross rent = Rs 5,000 per month · total outgoings = 25% of gross rent
    Estimated future life = 35 years
    Land = 200 m² @ Rs 2,000 per m²
    Rate of interest on capital = 10%; rate of redemption of capital = 5%

    Net annual income

    gross annual rent = 5,000 × 12 = Rs 60,000 outgoings = 25% of 60,000 = Rs 15,000 ---------- net annual income = Rs 45,000

    Year's purchase — dual rate

    sinking fund coefficient, s = 5%, n = 35 years (1.05)35 = 5.5160 S = 0.05 / ( 5.5160 − 1 ) = 0.05 / 4.5160 = 0.011072 YP = 1 / ( i + S ) = 1 / ( 0.10 + 0.011072 ) = 1 / 0.111072 = 9.0032

    Value of the building and of the land

    value of building = 45,000 × 9.0032 = Rs 4,05,143.68 value of land = 200 × 2,000 = Rs 4,00,000.00 --------------- fair value of the property = Rs 8,05,143.68
    Fair value of the property = Rs 8,05,143.68, say Rs 8,05,144 — of which the building accounts for Rs 4,05,144 and the land Rs 4,00,000.

    "Rate of redemption of capital" is simply another name for the sinking fund rate, so the dual-rate year's purchase applies. The land is added at its market value and is not capitalized, because land does not depreciate and its value is already reflected in the market rate.

    ENCE 351 §7.2 and §7.4.

  4. Define valuation. What are the purposes of valuation? Explain the factors affecting value of the property. Or Workout the value of a Cinema hall from the following data:
    • i) Cost of land = Rs. 5 crore
    • ii) Gross income = Rs. 2 crore
    • iii) Operating cost = 40% of gross income
    • iv) Repair and maintenance of machineries = 5% of capital cost, where capital cost is Rs. 40 lakh
    • v) Repair of hall = 5% of gross income
    • vi) Sinking fund for machineries whose life is estimated 25 years @ 4% after allowing 10% scrap value
    • vii) Insurance premium = Rs. 50,000 per year
    • viii) Assume year’s purchase for 60 years at 8% and redemption of capital at 10%
    [2+3+3 or 8] (CM 2070 Magh, Q.13)
    The last part of the theory option belongs to Section 7.3 and the alternative numerical to Section 7.4.
    Solution

    The paper offers a choice. Both alternatives are answered below.

    EITHER — Valuation: definition, purposes and factors

    Valuation. The art and science of estimating the fair present value of a property — land, building, factory or other engineering structure — on the basis of its present condition, its income-earning capacity, its future life, and the prevailing market conditions.

    Purposes of valuation — why it is required

    1. Buying and selling — to fix a fair price for both parties.
    2. Rent fixation — standard rent is normally 6–10% of the value.
    3. Security of a loan / mortgage — a bank lends only a fraction of the valuated amount.
    4. Taxation — property tax, house tax, wealth tax and municipal rates are assessed on value.
    5. Compulsory acquisition by government, to fix the compensation payable.
    6. Insurance — to fix the sum insured and the premium.
    7. Probate, partition and inheritance — to divide property among heirs.
    8. Court cases and arbitration — to settle disputes.
    9. Auction — to fix the upset (reserve) price.
    10. Speculation and investment decisions — to judge whether a purchase is worthwhile.
    11. Betterment charges, when a public work raises the value of adjoining land.

    Factors affecting the value of a property

    Physical factors

    • Location — the single most important factor; a central or commercial location commands a far higher value.
    • Size, shape and frontage of the plot; a regular plot with good road frontage is worth more than an irregular one.
    • Type, age and condition of the building, and its remaining useful life.
    • Quality of construction, specification and workmanship.
    • Availability of services — water supply, drainage, electricity, telephone, road access.
    • Soil condition and topography, and liability to flooding or landslide.

    Economic factors

    • Supply and demand for property in that locality.
    • Rental income the property can fetch, and the security of that income.
    • Prevailing rate of interest — a lower rate raises the year's purchase and hence the value.
    • Cost of construction at the present time.
    • Inflation and the general state of the economy.

    Legal and social factors

    • Clear title, freehold or leasehold tenure, and the unexpired lease period.
    • Encumbrances — mortgage, easement, right of way, tenancy.
    • Town planning restrictions — land use zoning, setback, floor area ratio, height limit.
    • Neighbourhood and social environment, proximity to schools, hospitals and markets.
    • Government policy — taxes, rent control, planned public works.

    OR — Value of the cinema hall

    Cost of land = Rs 5 crore · gross income = Rs 2 crore
    Operating cost = 40% of gross income
    Repair and maintenance of machinery = 5% of capital cost, capital cost = Rs 40 lakh
    Repair of hall = 5% of gross income
    Sinking fund for machinery: life 25 years @ 4%, after allowing 10% scrap
    Insurance premium = Rs 50,000 per year
    Year's purchase for 60 years at 8%, redemption of capital at 10%

    Annual sinking fund for the machinery

    amount to be recouped = capital cost − scrap = 40,00,000 × (1 − 0.10) = Rs 36,00,000 sinking fund coefficient, s = 4%, n = 25 years (1.04)25 = 2.66584 S = 0.04 / ( 2.66584 − 1 ) = 0.04 / 1.66584 = 0.024012 annual sinking fund = 36,00,000 × 0.024012 = Rs 86,443.07

    Total annual outgoings

    operating cost = 40% of 2,00,00,000 = Rs 80,00,000.00 repair of machinery = 5% of 40,00,000 = Rs 2,00,000.00 repair of hall = 5% of 2,00,00,000 = Rs 10,00,000.00 sinking fund for machinery = Rs 86,443.07 insurance premium = Rs 50,000.00 ---------------- total outgoings = Rs 93,36,443.07

    Net annual income

    net income = 2,00,00,000 − 93,36,443.07 = Rs 1,06,63,556.93

    Year's purchase — 60 years, 8% interest, 10% redemption

    (1.10)60 = 304.4816 S = 0.10 / ( 304.4816 − 1 ) = 0.10 / 303.4816 = 0.00032951 YP = 1 / ( 0.08 + 0.00032951 ) = 1 / 0.08032951 = 12.4487

    Value of the property

    capitalized value of the hall = 1,06,63,556.93 × 12.4487 = Rs 13,27,47,691.81 add cost of land = Rs 5,00,00,000.00 -------------------- total value of the cinema hall property = Rs 18,27,47,691.81
    Value of the cinema hall = Rs 18,27,47,692, i.e. about Rs 18.27 crore.

    This is the profit-based method, used for a commercial property whose worth depends on the business carried on in it. Note that the sinking fund is provided for the machinery only (life 25 years), not for the building (life 60 years) — the building's finite life is already allowed for in the year's purchase.

    ENCE 351 §7.1 and §7.4.

Valuation is the art of estimating the fair present value of a property — land, a building, a factory or any other engineering asset. Estimating asks what a thing will cost to build; valuation asks what it is worth now, in its present condition and location.

Purposes of valuation

  1. Buying or selling a property — to fix a fair price.
  2. Mortgage or security — a bank lends against the valued worth.
  3. Rent fixation — standard rent is normally 6–10% of the valuation.
  4. Taxation — property tax, wealth tax, house tax and municipal rates are levied on value.
  5. Compulsory acquisition — compensation when land is taken for a public project.
  6. Insurance — to fix the sum insured and to settle a fire or earthquake claim.
  7. Partition of property among co-owners or heirs.
  8. Court cases and arbitration, and compensation for damage caused by fire, flood or war.
  9. Auction and speculation, and to judge an investment.

Principles of valuation

A valuer must be more than an estimator: the work calls for knowledge of planning and design, of building construction, of the local market, and of the administrative law — town planning rules, building by-laws, rent control and local taxes. The following principles are observed:

  1. Value depends on supply and demand for that kind of property in that locality.
  2. Value depends on the design, specification and quality of the materials used.
  3. Value depends on the location of the property.
  4. Value varies with the purpose for which the valuation is made — the figure for insurance is not the figure for sale.
  5. Value varies with time; a valuation is valid only on its stated date.
  6. The valuer must be impartial and must inspect the property personally.

Pandey & Katwal, Complete Manual §7.1–7.3.

7.2 Concept of cost and value2074206720662065

Past Exam Questions on this Topic

  1. Distinguish clearly between:
    • i) Value and cost
    • ii) Salvage value and scrap value
    • iii) Cost based method of valuation and development method of valuation (Item iii also belongs to Section 7.4.)
    [6] (2067 Poush, Q.3(a))
    Solution

    i) Value and cost

    CostValue
    MeaningThe actual money spent in producing or acquiring the propertyThe present worth of the property to its owner or in the market
    NatureA historical fact — fixed once incurredAn estimate — changes with time, place and circumstances
    Depends onQuantities, rates, materials and labour actually usedDemand and supply, location, income, utility, scarcity
    Changes with time?No — it is a recordYes — it may rise or fall
    ExampleA house built 25 years ago at a cost of Rs 22 lakhThe same house may be worth Rs 1.5 crore today, mostly because of the land

    For a property to have value it must satisfy four conditions: it must have utility (be capable of satisfying a want), be scarce (limited in supply), be transferable (have a clear, marketable title), and command effective demand (there must be a buyer able and willing to pay).

    ii) Salvage value and scrap value

    Scrap value. The value of the dismantled material of a property at the end of its useful life — the broken bricks, steel, timber and other debris sold as material, after deducting the cost of demolition. It is usually taken as about 10% of the cost of construction. A building at the end of its life has scrap value only.

    Salvage value. The value of a property or machine at the end of its useful life to its present owner, when it is sold without being dismantled — it can still be used by somebody else for the same or another purpose. A machine sold second-hand at the end of its economic life to the present user has salvage value.

    Scrap valueSalvage value
    ConditionDismantled — sold as materialNot dismantled — sold as a whole, still usable
    Utility leftNone as a structure; only the material has worthStill serviceable to another user
    Demolition costDeductedNot involved
    Typical value≈ 10% of construction costHigher — depends on the second-hand market
    ExampleAn old building pulled down; bricks and steel soldA concrete mixer sold to a smaller contractor after 10 years

    iii) Cost based method and development method of valuation

    Cost based methodDevelopment method
    PrincipleValue = present replacement cost of the building less depreciation, plus the present value of the landValue = estimated sale value after development, less the cost of development, professional and legal charges, and the developer's profit
    LooksBackward — at what has already been spent, brought to present pricesForward — at what the property will fetch once developed
    Applied toAn existing building, especially a self-occupied one with no rental recordUndeveloped land having development potential; land acquisition for a colony
    Key inputPlinth area rate, age, total life, scrap valueSale rate of developed plots, area lost to roads and parks, development cost, profit margin
    WeaknessCost is not always value; it ignores the income the property earnsDepends heavily on assumed future sale prices and on the profit margin

    ENCE 351 §7.2 and §7.4.

    • a) Differentiate between cost and value. Explain different factors affecting valuation of property.
    • b) A building with plinth area 200 m² was constructed 25 years ago at a cost of Rs. 22 lakhs in a land of area 500 m². Rate of land at present is Rs. 25,000 per m². Current construction rate of similar building is Rs. 25,000 per m². If the life of the building is 60 years and scrap value 10%, find the present value of the property using straight line method of depreciation.
    [6+6] (CM 2073 Magh, Q.4)
    The second half of part a belongs to Section 7.3 and part b to Section 7.4.
    Solution

    a) Cost distinguished from value, and factors affecting valuation

    CostValue
    MeaningThe actual money spent in producing or acquiring the propertyThe present worth of the property to its owner or in the market
    NatureA historical fact — fixed once incurredAn estimate — changes with time, place and circumstances
    Depends onQuantities, rates, materials and labour actually usedDemand and supply, location, income, utility, scarcity
    Changes with time?No — it is a recordYes — it may rise or fall
    ExampleA house built 25 years ago at a cost of Rs 22 lakhThe same house may be worth Rs 1.5 crore today, mostly because of the land

    For a property to have value it must satisfy four conditions: it must have utility (be capable of satisfying a want), be scarce (limited in supply), be transferable (have a clear, marketable title), and command effective demand (there must be a buyer able and willing to pay).

    Factors affecting the value of a property

    Physical factors

    • Location — the single most important factor; a central or commercial location commands a far higher value.
    • Size, shape and frontage of the plot; a regular plot with good road frontage is worth more than an irregular one.
    • Type, age and condition of the building, and its remaining useful life.
    • Quality of construction, specification and workmanship.
    • Availability of services — water supply, drainage, electricity, telephone, road access.
    • Soil condition and topography, and liability to flooding or landslide.

    Economic factors

    • Supply and demand for property in that locality.
    • Rental income the property can fetch, and the security of that income.
    • Prevailing rate of interest — a lower rate raises the year's purchase and hence the value.
    • Cost of construction at the present time.
    • Inflation and the general state of the economy.

    Legal and social factors

    • Clear title, freehold or leasehold tenure, and the unexpired lease period.
    • Encumbrances — mortgage, easement, right of way, tenancy.
    • Town planning restrictions — land use zoning, setback, floor area ratio, height limit.
    • Neighbourhood and social environment, proximity to schools, hospitals and markets.
    • Government policy — taxes, rent control, planned public works.

    b) Present value of the property — straight line depreciation

    Plinth area = 200 m² · constructed 25 years ago at a cost of Rs 22 lakh
    Land = 500 m², present rate Rs 25,000 per m²
    Current construction rate for a similar building = Rs 25,000 per m²
    Life of the building = 60 years · scrap value = 10%

    Present replacement cost of the building

    The Rs 22 lakh spent 25 years ago is the historical COST and is not used in the valuation. The building must be valued at what it would cost to build TODAY: replacement cost = 200 m² × Rs 25,000 = Rs 50,00,000

    Depreciation by the straight line method

    scrap value S = 10% of 50,00,000 = Rs 5,00,000 annual depreciation D = ( C − S ) / n = ( 50,00,000 − 5,00,000 ) / 60 = 45,00,000 / 60 = Rs 75,000 per year depreciation in 25 years = 75,000 × 25 = Rs 18,75,000

    Depreciated value of the building

    present value of building = 50,00,000 − 18,75,000 = Rs 31,25,000

    Value of the land, and the total

    land = 500 m² × Rs 25,000 = Rs 1,25,00,000 building = Rs 31,25,000 ---------------- present value of the property = Rs 1,56,25,000
    Present value of the property = Rs 1,56,25,000 (land Rs 1.25 crore + building Rs 31.25 lakh).

    Two traps in this question. First, the Rs 22 lakh original cost is a distractor — depreciation is always applied to the present replacement cost, not to the historical cost. Second, notice how completely the land dominates: it is 80% of the value. Land does not depreciate; buildings do.

    ENCE 351 §7.2 and §7.4.

  2. Write short notes on:
    • (i) Scrap value
    • (ii) Depreciation
    • (iii) Sinking fund
    • (iv) Capitalized value
    [6] (2074 Ashwin, Q.5(b))
    Solution

    (i) Scrap value. The value of the dismantled material of a property at the end of its useful life — the old bricks, steel, timber and other debris sold as material, after deducting the cost of demolition. Usually taken as about 10% of the cost of construction. If the demolition cost exceeds the sale proceeds, the scrap value is negative.

    (ii) Depreciation. The gradual loss in the value of a property due to its use, wear and tear, decay and age.

    straight line : D = ( C − S ) / n per year value after m years = C − m × D constant percentage : p = 1 − ( S / C )1/n

    Other methods are the sinking fund method and the quantity survey method. Depreciation is physical and gradual, and is retarded by good maintenance — unlike obsolescence, which is functional and sudden.

    (iii) Sinking fund. A fund created by setting aside a fixed sum out of the income of a property every year so that, with compound interest, it accumulates to the amount needed to rebuild or replace the property at the end of its life.

    I = S × i / [ (1+i)n − 1 ] S = amount required at the end ( cost less scrap ) i = rate of compound interest, n = number of years

    It is treated as an outgoing in the valuation, because that money is not available to the owner as income.

    (iv) Capitalized value. The amount of capital whose interest, at the prevailing rate, would yield the net annual income actually received from the property — that is, the value of the property on an income basis.

    capitalized value = net annual income × year's purchase YP for perpetuity = 100 / rate = 1 / i YP for n years at i = [ 1 − (1+i)−n ] / i YP dual rate = 1 / ( i + S ) example : net income Rs 1,20,000 capitalized at 8% YP = 100/8 = 12.5 capitalized value = 1,20,000 × 12.5 = Rs 15,00,000

    ENCE 351 §7.2 and §7.4.

  3. Write short notes on (any three):
    • i) Overhead charge
    • ii) Task or out turn of work
    • iii) Salvage value and scrap value
    • iv) Sinking fund (Items i and ii also belong to Chapter 3.)
    [3×2] (2067 Ashadh, Q.2(c))
    Solution

    Answer any three. All four are given below.

    i) Overhead charges. The expenses a contractor must incur to run his business which cannot be charged directly to any one item of work. They are recovered by adding a percentage — usually 5–10% — in the analysis of rates.

    • General overheads — office rent, salaries of head-office staff, stationery, telephone, travelling, advertisement, insurance, interest on capital, depreciation of plant, legal and audit charges.
    • Job overheads — expenses of that particular work: site office, site supervisor's pay, watchman, temporary shed, water and power connection, tools, and safety arrangements.

    ii) Task or out-turn of work. The quantity of work that an average workman of a trade can complete in one working day of eight hours. It is the figure that converts a quantity of work into man-days, and so is the basis of the labour component in every rate analysis.

    Item of workTypical out-turn per artisan per day
    Earthwork in ordinary soil3.0 m³
    Brickwork in superstructure1.0 m³
    Random rubble stone masonry0.8 m³
    12 mm cement plastering8.0 m²
    Cement concrete3.0 m³ (for a gang)

    The out-turn depends on the skill of the workman, the nature and height of the work, supervision, weather and the tools provided.

    iii) Salvage value and scrap value.

    Scrap value. The value of the dismantled material of a property at the end of its useful life — the broken bricks, steel, timber and other debris sold as material, after deducting the cost of demolition. It is usually taken as about 10% of the cost of construction. A building at the end of its life has scrap value only.

    Salvage value. The value of a property or machine at the end of its useful life to its present owner, when it is sold without being dismantled — it can still be used by somebody else for the same or another purpose. A machine sold second-hand at the end of its economic life to the present user has salvage value.

    Scrap valueSalvage value
    ConditionDismantled — sold as materialNot dismantled — sold as a whole, still usable
    Utility leftNone as a structure; only the material has worthStill serviceable to another user
    Demolition costDeductedNot involved
    Typical value≈ 10% of construction costHigher — depends on the second-hand market
    ExampleAn old building pulled down; bricks and steel soldA concrete mixer sold to a smaller contractor after 10 years

    iv) Sinking fund.

    Sinking fund. A fund created by setting aside a fixed sum out of the income of a property every year, so that with accumulated compound interest it amounts, at the end of the useful life, to the sum needed to rebuild or replace the property. The annual instalment is

    I = S × i / [ (1+i)n − 1 ] S = total amount required at the end ( cost less scrap value ) i = rate of compound interest on the fund n = number of years

    The sinking fund instalment is treated as an outgoing in the valuation, because it is money that must be set aside and is therefore not available as income.

    ENCE 351 §6.1, §6.3 and §7.2.

  4. Write short notes on (any three):
    • i) Approximate estimate
    • ii) Revised estimate
    • iii) Centre line method
    • iv) Capitalized value (Items i and ii belong to Chapter 3 and item iii belongs to Chapter 2.)
    [6] (2066 Bhadra, Q.2(b))
    Solution

    Answer any three. All four are given below.

    i) Approximate estimate. A rough estimate prepared at the proposal stage, before detailed drawings exist, from a single overall parameter — plinth area, cube content, cost per bed, per student, per km of road. It is used to judge whether the scheme is worth pursuing, to obtain administrative approval and to provide the amount in the budget. It is supported by a report, a site plan and line drawings, and is accurate only to about ±15–20%.

    ii) Revised estimate. A fresh detailed estimate prepared for a work already sanctioned, when the expenditure exceeds or is likely to exceed the sanctioned amount by more than 5%, or when the rates or the design change materially. It shows the original and the revised quantity and cost of every item side by side, with the reason for each variation, and must be sanctioned afresh by the competent authority.

    iii) Centre line method. A method of taking out quantities in which the total centre-line length of all the walls is found once and then multiplied by the breadth and the depth of each item in turn. Where walls meet, half the breadth of the item is deducted for each junction, because that corner would otherwise be counted twice.

    deduction = (number of junctions) × ½ × breadth of the item quantity = (total centre-line length − deduction) × breadth × height

    It is the quickest method and is best suited to buildings in which all the walls have the same thickness.

    iv) Capitalized value. The amount of capital whose interest, at the prevailing rate, would yield the net annual income actually received from the property. It is the value of the property on an income basis:

    capitalized value = net annual income × year's purchase year's purchase (perpetuity) = 100 / rate of interest = 1 / i net annual income = gross annual income − all outgoings

    For example, a property yielding a net income of Rs 1,20,000 a year, capitalised at 8%, has a capitalized value of 1,20,000 × (100/8) = 1,20,000 × 12.5 = Rs 15,00,000.

    ENCE 351 Chapters 2, 3 and 7.

  5. Write short notes on (any three):
    • i) Contingency
    • ii) Bill of quantities
    • iii) Distress value
    • iv) Depreciation (Items i and ii also belong to Chapter 3.)
    [3×2] (2065 Shrawan, Q.2(b))
    Solution

    Answer any three. All four are given below.

    i) Contingency. A lump-sum provision, normally 3–5% of the estimated cost, added to every estimate to meet unforeseen and petty expenses and minor omissions that cannot be itemised at the time of estimating — small changes at site, small variations in rates, incidental charges. It is not meant to pay for a change in the scope of the work, which requires a supplementary or revised estimate, and it can be spent only with the sanction of the competent authority.

    ii) Bill of quantities. A tabulated schedule of every item of work in a project, giving a brief description, the estimated quantity, the unit, the rate and the amount. It is issued with the tender documents so that all contractors price the same quantities and their offers can be compared item by item, and it is afterwards used to measure and pay for the work actually executed and to value variations.

    iii) Distress value. The value that a property fetches when it is sold under compulsion or unfavourable conditions instead of in an open, willing market — for instance in a forced auction to recover a debt, in an urgent sale to raise money, during a partition dispute, or where the title is doubtful or the property is encumbered. It is always appreciably lower than the fair market value, typically by 15–30%, because the seller has neither the time nor the freedom to wait for the right purchaser.

    iv) Depreciation.

    Depreciation. The gradual loss in the value of a property due to its use, wear and tear, decay and age. It is a physical deterioration, and it is recovered by charging a part of the cost against the income each year.

    Methods of calculating it:

    1. Straight line method — equal amount every year:
    D = ( C − S ) / n per year value after m years = C − m × D C = original cost, S = scrap value, n = useful life in years
    1. Constant percentage (declining balance) method — a fixed percentage of the book value each year: p = 1 − (S/C)1/n.
    2. Sinking fund method — depreciation is the annual sinking fund instalment plus interest.
    3. Quantity survey method — the property is examined in detail and the loss in each part is assessed. The most accurate and the most laborious.

    ENCE 351 §3.6 and §7.2.

  6. Write short note on: Scrap Value and Salvage value. [short note] (CM 2075 Bhadra, Q.8(d))
    Solution

    Scrap value. The value of the dismantled material of a property at the end of its useful life — the broken bricks, steel, timber and other debris sold as material, after deducting the cost of demolition. It is usually taken as about 10% of the cost of construction. A building at the end of its life has scrap value only.

    Salvage value. The value of a property or machine at the end of its useful life to its present owner, when it is sold without being dismantled — it can still be used by somebody else for the same or another purpose. A machine sold second-hand at the end of its economic life to the present user has salvage value.

    Scrap valueSalvage value
    ConditionDismantled — sold as materialNot dismantled — sold as a whole, still usable
    Utility leftNone as a structure; only the material has worthStill serviceable to another user
    Demolition costDeductedNot involved
    Typical value≈ 10% of construction costHigher — depends on the second-hand market
    ExampleAn old building pulled down; bricks and steel soldA concrete mixer sold to a smaller contractor after 10 years

    ENCE 351 §7.2.

Cost, price and value

TermMeaning
CostThe actual expenditure incurred in producing or constructing the property — materials, labour, plant, overheads.
PriceThe cost plus the producer's profit — what is actually paid in a transaction.
ValueThe present worth of the property to its owner, depending on its utility, condition, location and the demand for it.

Cost and value are independent. A house that cost Rs 1 crore to build in a remote village may be worth Rs 40 lakh; an old house in central Kathmandu that cost Rs 5 lakh decades ago may be worth Rs 5 crore because of the land beneath it.

The vocabulary of valuation

TermDefinition
Scrap valueThe value of the dismantled material at the end of the property's useful life, after deducting the cost of demolition. Usually taken as about 10% of the cost of construction. A building whose materials are worthless has nil scrap value.
Salvage valueThe value of a property at the end of its useful life without being dismantled — it can still be sold and used by someone else, as a machine sold second-hand.
Book valueThe value shown in the account books: original cost less the total depreciation charged to date. It falls year by year and finally equals the scrap value.
Market valueThe amount the property would fetch if sold in the open market on the date of valuation — a matter of supply and demand.
Assessed valueThe value recorded by a municipality or tax authority for levying tax.
Distress valueThe lower value fetched when a property is sold under compulsion — bankruptcy, urgent need, a quarrel between owners.
Speculative valueThe value paid by a buyer who intends to resell at a profit.
Replacement valueThe cost of building the same property afresh at current rates.
Sinking fundThe fund built up by setting aside a fixed sum each year so that, at the end of the useful life, the accumulated amount replaces the property.
Year's purchase (YP)The number of years' net income whose present worth equals the capital value; the multiplier that converts annual income into capital value.
Capitalized valueThe capital sum whose interest at the prevailing rate equals the net annual income of the property: capitalized value = net annual income × year's purchase.
ObsolescenceLoss of value from causes other than physical wear — outdated design, change of fashion, new technology, change in locality or planning.
AnnuityThe annual periodic payment made for a stated number of years, or in perpetuity.

Sinking fund and year's purchase

sinking fund instalment I = S · i / [(1 + i)ⁿ − 1] S = total amount required at the end (cost − scrap value) i = rate of interest as a decimal n = life of the property in years
year's purchase (perpetuity) YP = 100 / rate of interest (%) = 1 / i year's purchase (deferred, n years) YP = [1 − (1 + i)−n] / i
capitalized value = net annual income × year's purchase

Net annual income is the gross rent less the outgoings — taxes, repairs (usually 1/12 to 1/6 of gross rent), management, insurance and the sinking fund instalment.

Depreciation

Depreciation is the loss in value of a property due to age, wear and tear, decay and obsolescence. It is the reason a building is worth less than it cost.

MethodBasisFormula
Straight lineEqual amount written off each yearD = (C − S) / n
Constant percentage (declining balance)A fixed percentage of the book value each yearp = 1 − (S/C)1/n
Sinking fundThe annual instalment plus interest replaces the assetD = (C − S) · i / [(1 + i)ⁿ − 1]
Quantity surveyEach part of the building examined and its own depreciation assessed— detailed inspection

C = original cost, S = scrap value, n = life in years, i = interest rate.

Depreciation is physical — wear, decay, age. Obsolescence is functional — the building is sound but out of date. Both reduce value, and an exam answer should distinguish them.

The three methods compared on one asset

A concrete mixer costing Rs 8,000, salvage value Rs 1,000 after 5 years, sinking fund at 6%.
YearStraight lineConstant percentageSinking fund
Depn.Book valueDepn.Book valueInstalmentInterestDepn.Book value
11,400.006,600.002,721.975,278.031,241.770.001,241.776,758.23
21,400.005,200.001,795.833,482.201,241.7774.511,316.285,441.94
31,400.003,800.001,184.812,297.401,241.77153.481,395.264,046.69
41,400.002,400.00781.681,515.721,241.77237.201,478.972,567.71
51,400.001,000.00515.721,000.001,241.77325.941,567.711,000.00
straight line : D = (8,000 − 1,000)/5 = Rs 1,400.00 every year constant percentage : p = 1 − (1,000/8,000)1/5 = 0.3402 = 34.02% sinking fund : D = (8,000 − 1,000) × 0.06 / [(1.06)⁵ − 1] = Rs 1,241.77 per year, plus interest on the fund

All three close on the salvage value of Rs 1,000 — that is the check. But they write the value off very differently: the constant percentage method is heaviest in the early years (Rs 2,722 in year 1), the sinking fund method is lightest at first and grows as interest accumulates, and the straight line method is flat. Machinery is usually depreciated by the constant percentage method because it does lose most of its value early; buildings by the straight line method.

Sinking fund method — depreciation after any number of years

The year-by-year table above is fine for five years, but an examination usually asks for the depreciation of a building m years into an n year life in one step. Two standard quantities are used:

sinking fund coefficient for the full life Sc = i / [ (1 + i)n − 1 ] amount to which Re 1 per annum accumulates in m years Am = [ (1 + i)m − 1 ] / i total depreciation in m years D = C × Sc × Am (1 + i)m − 1 i.e. D = C × --------------- ( the i cancels ) (1 + i)n − 1

Example. A building would cost Rs 25,00,000 to put up today and has a life of 80 years. It is 15 years old. Find the depreciation at 10% compound interest.

(1.10)15 = 4.177248 (1.10)80 = 2048.4002 4.177248 − 1 3.177248 D = ------------------ = ------------ = 0.001551845 of the cost 2048.4002 − 1 2047.4002 D = 25,00,000 × 0.001551845 = Rs 3,879.61 present value = 25,00,000 − 3,879.61 = Rs 24,96,120.39

Textbooks usually split this into two table look-ups — the sinking fund coefficient Sc = 0.0000488 and the amount of Re 1 per annum Am = 31.772 — and multiply them. Do the division in one step as above instead: Sc is so small that rounding it to three significant figures shifts the answer by over 1%. Two checks on the formula: put m = n and it gives D = C, so the whole cost is written off exactly at the end of the life; and notice how little is written off early — only 0.16% after 15 of 80 years. That is the character of the sinking fund method, and it is why a building depreciated this way is worth far more at mid-life than one depreciated on a straight line.

Obsolescence — internal and external

Obsolescence is the loss in value due to change in fashion, design, construction or utility, or to new inventions making the property inadequate. It is classified by where the cause lies:

Internal obsolescenceExternal obsolescence
Poor or eccentric original designPoor original location
Change in the type of constructionChange in the character of the district
Change in the kind of constructionSpecific detrimental influences — a factory, stockyard or public building nearby, traffic, noise
Change in utility demandZoning laws

The sharpest distinction to remember: depreciation can be calculated by any of four methods, whereas there is no method of calculating obsolescence — it is assessed by judgement. And depreciation grows with age, while a brand new building can suffer obsolescence from the day it opens.

Three terms that are asked as short notes

Annuities are of three kinds:

KindMeaning
Annuity certainPayable at the beginning of each period and continued for a fixed number of periods
Perpetual annuityReceivable for an indefinite period — this is the case for which YP = 100 / rate
Deferred annuityCommences only after a stated number of years from the date the capital was invested

Life of the various items of a building

Almost every valuation question says "assume suitable data". The life is the figure most often needed, and it can be justified from this standard table rather than guessed:

Item of workLife
Masonry
Brickwork, boulder masonry or cut stone work in lime or cement100 years and above
Brickwork in clay, coursed rubble in mud; brick and rubble arches100 years
Sun-dried brickwork in clay75 years
Flooring
Cement concrete, granolithic or stone flooring50 years
Brick-on-edge or flat flooring over 7.5 cm lime concrete40 years
Terraced floor or lime concrete20 years
Roofing
Iron work in roofing80 years
RCC and RB roofing, terraced roofing over stone flags75 years
Sal wood work in roof60 years
G.I. sheet roofing, 22 B.W.G.50 years
Pine wood ceiling30 years
Allahabad lock tiling25 years
Sal ballies in roof20 years
Country wood in roof15 years
Doors, windows and iron work
Teak or sal wood doors and windows40 years
Country wood doors and windows30 years
Wrought iron work80 years
Rolled steel joist75 years

For a whole building take the life of its governing element: an RCC framed building is normally valued on a life of 70–80 years and a load-bearing masonry building on 100 years. Whichever you adopt, state it — the marks are for the justification, not for a particular number.

Where the arithmetic is heavy, valuation tables (Miram's tables are the ones generally used) give year's purchase, sinking fund coefficients and present values as a ready reckoner.

Pandey & Katwal, Complete Manual ch.7 (valuation), book pp.134–147; depreciation methods, the internal / external classification of obsolescence, amortization and the kinds of annuity follow Chakraborti, Estimating, Costing and Specification, ch. XV §15-7 to §15-15; the table of lives is from B. N. Dutta, Estimating and Costing in Civil Engineering, ch. on valuation, book p.629.

7.3 Factors affecting the value of the property2068

Past Exam Questions on this Topic

  1. What are the factors which should be kept in mind while evaluating fair and reasonable value of the property? The factors affecting the value of a property are also asked in Q3(a) [CM 2078 Chaitra], Q6 [CM 2070 Magh] and Q8(a) [CM 2073 Magh] of the previous sections. [4] (2068 Baishakh, Q.4(a))
    Solution

    Factors to be kept in mind while evaluating the fair and reasonable value of a property

    Factors affecting the value of a property

    Physical factors

    • Location — the single most important factor; a central or commercial location commands a far higher value.
    • Size, shape and frontage of the plot; a regular plot with good road frontage is worth more than an irregular one.
    • Type, age and condition of the building, and its remaining useful life.
    • Quality of construction, specification and workmanship.
    • Availability of services — water supply, drainage, electricity, telephone, road access.
    • Soil condition and topography, and liability to flooding or landslide.

    Economic factors

    • Supply and demand for property in that locality.
    • Rental income the property can fetch, and the security of that income.
    • Prevailing rate of interest — a lower rate raises the year's purchase and hence the value.
    • Cost of construction at the present time.
    • Inflation and the general state of the economy.

    Legal and social factors

    • Clear title, freehold or leasehold tenure, and the unexpired lease period.
    • Encumbrances — mortgage, easement, right of way, tenancy.
    • Town planning restrictions — land use zoning, setback, floor area ratio, height limit.
    • Neighbourhood and social environment, proximity to schools, hospitals and markets.
    • Government policy — taxes, rent control, planned public works.

    A valuer should also be satisfied on three practical points before signing: that the title is clear and marketable, that the property is free of encumbrances, and that the comparable sales relied upon are genuine arm's-length transactions and not distress or related-party sales.

    ENCE 351 §7.3.

Value is not a property of the building alone. These are the factors the examiners expect:

  1. Location — the single strongest factor: nearness to the town centre, to the road, to schools, markets, hospitals and transport.
  2. Size, shape and frontage of the plot; a regular plot with good road frontage is worth more than an irregular land-locked one.
  3. Type and quality of construction — the structural system, specification, materials and workmanship.
  4. Age and condition of the building, and how well it has been maintained.
  5. Availability of services — water supply, drainage, electricity, telephone, sewerage.
  6. Supply and demand in that locality at that time.
  7. Legal status — clear title, tenancy, encumbrance, litigation, or a sitting tenant protected by rent control.
  8. Town planning and by-laws — permitted land use, floor area ratio, height limit, set-backs, right of way.
  9. Obsolescence — outdated plan, poor lighting or ventilation, no lift or parking.
  10. Rent obtainable and the return the property yields.
  11. Political and economic conditions — interest rates, inflation, stability, and government policy on land.
  12. Hazard — liability to flood, landslide, earthquake or fire.

Pandey & Katwal, Complete Manual §7.4.

7.4 Methods of valuation of properties20742068206720662065

Past Exam Questions on this Topic

  1. Discuss the various methods of valuation of the property. [4] (2068 Baishakh, Q.4(b))
    Solution

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    ENCE 351 §7.4.

  2. Mention various method of valuation and under what circumstances each one is prepared? [5] (2065 Shrawan, Q.4(a))
    Solution

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    Choosing the method is itself part of the answer. Ask what the property is: if it earns rent, capitalize the rent; if it is self-occupied, use the cost method; if it is bare land in an active market, compare it; if it has development potential, use the development method; if a business is run in it, capitalize the profit.

    ENCE 351 §7.4.

  3. What is valuation? Write different methods of valuation. [6] (CM 2074 Bhadra, Q.7(a))
    Solution

    Valuation. The art and science of estimating the fair present value of a property — land, building, factory or other engineering structure — on the basis of its present condition, its income-earning capacity, its future life, and the prevailing market conditions.

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    ENCE 351 §7.4.

  4. Write various methods of valuation of properties and elaborate concept of depreciations. [equal marks] (CM 2072 Ashwin, Q.7(b))
    Solution

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    Concept of depreciation

    Depreciation. The gradual loss in the value of a property due to its use, wear and tear, decay and age. It is a physical deterioration, and it is recovered by charging a part of the cost against the income each year.

    Methods of calculating it:

    1. Straight line method — equal amount every year:
    D = ( C − S ) / n per year value after m years = C − m × D C = original cost, S = scrap value, n = useful life in years
    1. Constant percentage (declining balance) method — a fixed percentage of the book value each year: p = 1 − (S/C)1/n.
    2. Sinking fund method — depreciation is the annual sinking fund instalment plus interest.
    3. Quantity survey method — the property is examined in detail and the loss in each part is assessed. The most accurate and the most laborious.

    Depreciation and obsolescence

    DepreciationObsolescence
    CausePhysical — wear and tear, decay, age, weatheringFunctional — the property becomes out of date, out of fashion or unsuitable for present needs
    Depends onThe age and condition of the property itselfChanges outside the property — new design, new technology, changed taste, changed town planning
    RateSlow and steady; can be calculated year by yearSudden and unpredictable; cannot be forecast
    Can it be prevented?Slowed by good maintenance and repairNo — maintenance does not help at all
    ExamplePlaster cracking and timber decaying in a 40-year-old houseA sound old house with no lift, small rooms and no parking, unsaleable beside modern apartments

    A building can be physically sound and still lose most of its value through obsolescence — which is why a valuer must consider both.

    ENCE 351 §7.2 and §7.4.

  5. Explain the various methods of valuation of the properties. [5] (CM 2071 Magh, Q.7(b))
    Solution

    Methods of valuation of a property

    MethodHow the value is foundUsed when
    1. Rental / capitalization methodNet annual income × year's purchase. The net income is the gross rent less all outgoingsThe property is rented and a reliable income record exists. The standard method for tenanted buildings
    2. Cost based (land and building) methodPresent replacement cost of the building, less depreciation, plus the present value of the landSelf-occupied buildings, or new buildings with no rental record; also for insurance
    3. Plinth area methodPlinth area × present plinth area rate, less depreciation, plus landA quick valuation of an ordinary building when a comparable recent rate is available
    4. Comparative / market methodCompare with the price actually fetched by similar properties recently sold in the same locality, adjusting for differencesOpen land and residential property in an active market
    5. Development methodEstimated sale value after development, less the cost of development, the professional and legal charges and the developer's profitUndeveloped land with development potential, and land acquisition for a colony
    6. Profit / income based methodNet profit of the business carried on is capitalizedCommercial properties — cinema, hotel, cold storage, petrol pump — where the value depends on the business
    7. Depreciation method (Ross / Dube)Value found by applying a depreciation formula to the cost, based on the age and total lifeOld buildings, and as a check on other methods
    8. Belting methodA deep urban plot is divided into belts parallel to the road; the front belt is valued highest, and the rear belts at reducing ratesDeep urban plots with road frontage

    ENCE 351 §7.4.

    • a) Explain the situation where the following method of valuation will be used:
      • (i) Cost based method
      • (ii) Plinth area method
      • (iii) Development method
    • b) Work out the valuation of a Cinema hall with the following data:
      • (i) Cost of land = Rs. 15,00,000
      • (ii) Gross income = Rs. 90,00,000
      • (iii) Expenses undergone per year to run the cinema including staff salary, electricity charges, municipal taxes, stationery and printing etc. = 30% of gross income
      • (iv) Repair and maintenance of machinery, plant and equipment at 5% of their capital cost, which is Rs. 55,00,000
      • (v) Sinking fund for machinery, plant and equipment whose life is estimated as 25 years at 5% after allowing 10% scrap value
      • (vi) Insurance premium is Rs. 60,000 per annum Assume year’s purchase for 60 years at 8% and redemption of capital at 4% and repair of hall at 2% of gross income. Numerical Problems
    [3+5] (CM 2070 Bhadra, Q.4)
    Solution

    a) Situations in which each method of valuation is used

    (i) Cost based method. Value = present replacement cost of the building, less depreciation, plus the present value of the land. Used when the property is self-occupied and has no rental record; when the building is special or unusual (a factory, a school, a place of worship) so that no comparable sale exists; for insurance valuation; and for a newly built property.

    (ii) Plinth area method. Value = plinth area × present plinth area rate, less depreciation, plus land. Used for a quick valuation of an ordinary building — a residence or an office — when the rate of a recently completed similar building in the same locality is available. It is the standard method for bank loan valuations and for government property.

    (iii) Development method. Value = estimated sale value after development, less the development cost, professional and legal charges and the developer's profit. Used for undeveloped land having development potential — agricultural land ripe for a housing colony, a large plot to be subdivided — and for fixing the compensation when a planning authority acquires land for a colony.

    b) Valuation of the cinema hall

    Cost of land = Rs 15,00,000 · gross income = Rs 90,00,000
    Running expenses (salary, electricity, taxes, stationery) = 30% of gross income
    Repair and maintenance of machinery, plant and equipment = 5% of their capital cost of Rs 55,00,000
    Sinking fund for machinery: life 25 years @ 5%, after allowing 10% scrap
    Insurance premium = Rs 60,000 per annum
    Repair of hall = 2% of gross income
    Year's purchase for 60 years at 8%, redemption of capital at 4%

    Annual sinking fund for the machinery

    amount to be recouped = 55,00,000 × (1 − 0.10) = Rs 49,50,000 sinking fund coefficient, s = 5%, n = 25 years (1.05)25 = 3.38635 S = 0.05 / ( 3.38635 − 1 ) = 0.05 / 2.38635 = 0.020952 annual sinking fund = 49,50,000 × 0.020952 = Rs 1,03,714.66

    Total annual outgoings

    running expenses = 30% of 90,00,000 = Rs 27,00,000.00 repair of machinery = 5% of 55,00,000 = Rs 2,75,000.00 repair of hall = 2% of 90,00,000 = Rs 1,80,000.00 sinking fund for machinery = Rs 1,03,714.66 insurance premium = Rs 60,000.00 ---------------- total outgoings = Rs 33,18,714.66

    Net annual income

    net income = 90,00,000 − 33,18,714.66 = Rs 56,81,285.34

    Year's purchase — 60 years, 8% interest, 4% redemption

    (1.04)60 = 10.5196 S = 0.04 / ( 10.5196 − 1 ) = 0.04 / 9.5196 = 0.0042018 YP = 1 / ( 0.08 + 0.0042018 ) = 1 / 0.0842018 = 11.8762

    Value of the property

    capitalized value of the hall = 56,81,285.34 × 11.8762 = Rs 6,74,72,219.02 add cost of land = Rs 15,00,000.00 ------------------- total value of the cinema hall = Rs 6,89,72,219.02
    Value of the cinema hall = Rs 6,89,72,219, i.e. about Rs 6.90 crore.

    The sinking fund is provided only for the machinery, whose 25-year life is much shorter than the 60-year life of the hall. The hall's own finite life is already accounted for by using a year's purchase for 60 years rather than for perpetuity.

    ENCE 351 §7.4.

  6. Workout the valuation of a cold storage with the following data:
    • i) Cost of land = Rs. 20,00,000.00
    • ii) Gross income per year = Rs. 95,00,000.00
    • iii) Staff salary, electricity charges at 25% of gross income
    • iv) Repair and maintenance of machinery, plants, equipments etc. at 5% of their capital cost, which is Rs. 15,00,000.00
    • v) Sinking fund for machinery, plants etc. with 25 yrs life at the rate of 4% after allowing 10% scrap value
    • vi) Insurance premium per year Rs. 15,000.00 Assume year’s purchase for 60 yrs at 8% and redemption of capital at 4%.
    [8] (2068 Baishakh, Q.4(c))
    Solution
    Cost of land = Rs 20,00,000 · gross income per year = Rs 95,00,000
    Staff salary and electricity charges = 25% of gross income
    Repair and maintenance of machinery and plant = 5% of their capital cost of Rs 15,00,000
    Sinking fund for machinery: life 25 years @ 4%, after allowing 10% scrap
    Insurance premium = Rs 15,000 per year
    Year's purchase for 60 years at 8%, redemption of capital at 4%

    Annual sinking fund for the machinery

    amount to be recouped = 15,00,000 × (1 − 0.10) = Rs 13,50,000 sinking fund coefficient, s = 4%, n = 25 years (1.04)25 = 2.66584 S = 0.04 / ( 2.66584 − 1 ) = 0.04 / 1.66584 = 0.024012 annual sinking fund = 13,50,000 × 0.024012 = Rs 32,416.15

    Total annual outgoings

    staff salary and electricity = 25% of 95,00,000 = Rs 23,75,000.00 repair of machinery = 5% of 15,00,000 = Rs 75,000.00 sinking fund for machinery = Rs 32,416.15 insurance premium = Rs 15,000.00 ---------------- total outgoings = Rs 24,97,416.15

    Net annual income

    net income = 95,00,000 − 24,97,416.15 = Rs 70,02,583.85

    Year's purchase — 60 years, 8% interest, 4% redemption

    (1.04)60 = 10.5196 S = 0.04 / ( 10.5196 − 1 ) = 0.0042018 YP = 1 / ( 0.08 + 0.0042018 ) = 11.8762

    Value of the property

    capitalized value of the cold storage = 70,02,583.85 × 11.8762 = Rs 8,31,64,256.56 add cost of land = Rs 20,00,000.00 ------------------- total valuation of the cold storage = Rs 8,51,64,256.56
    Valuation of the cold storage = Rs 8,51,64,257, i.e. about Rs 8.52 crore.

    ENCE 351 §7.4.

  7. A town planning authority has to acquire an area of 500000 m² for the development of new colony. After developing the area it is proposed to be sold at Rs. 50.00 per m². Workout the maximum compensation which can be given to the owners whose land is to be acquired for the development of the colony, assuming:
    • (i) Authority establishment charges 15% on the sale price
    • (ii) 40% area provided for roads, parks etc.
    • (iii) Colony improvement expenditure Rs. 8.00 per m²
    • (iv) Engineers and architect’s fee for surveying and planning the colony at 4% on the sale price
    [8] (2074 Ashwin, Q.5(a))
    Solution
    Area to be acquired = 5,00,000 m²
    Sale price after development = Rs 50.00 per m²
    (i) Authority establishment charges = 15% on the sale price
    (ii) Area provided for roads, parks etc. = 40%
    (iii) Colony improvement expenditure = Rs 8.00 per m²
    (iv) Engineer's and architect's fee = 4% on the sale price

    Saleable area

    area for roads, parks etc. = 40% saleable area = 5,00,000 × (1 − 0.40) = 5,00,000 × 0.60 = 3,00,000 m²

    Sale price of the developed plots

    sale price = 3,00,000 × Rs 50 = Rs 1,50,00,000

    Deductions

    i) establishment charges @ 15% of sale price = 0.15 × 1,50,00,000 = Rs 22,50,000 ii) engineer's and architect's fee @ 4% = 0.04 × 1,50,00,000 = Rs 6,00,000 iii) colony improvement expenditure = 5,00,000 m² × Rs 8 = Rs 40,00,000 -------------- total deductions = Rs 68,50,000

    Maximum compensation payable

    compensation = sale price − total deductions = 1,50,00,000 − 68,50,000 = Rs 81,50,000 rate per m² = 81,50,000 / 5,00,000 = Rs 16.30 per m²
    Maximum compensation that can be given to the land owners = Rs 81,50,000, i.e. Rs 16.30 per m².

    The improvement expenditure is incurred on the whole 5,00,000 m², while the income arises only from the saleable 3,00,000 m² — applying Rs 8 to the saleable area instead would wrongly raise the compensation by Rs 16 lakh. The compensation is finally expressed per m² of the acquired area, because that is what each owner is paid for.

    ENCE 351 §7.4.

  8. A town planning authority has to acquire an area of 4,50,000 m² for the development of a new colony. After developing the area, it is proposed to be sold at Rs. 40.00 per m². Work out the maximum compensation which shall be given to the land owners, assuming:
    • i) Town planning authority’s establishment charges @ 15% on the sale price
    • ii) 35% area provided for roads, parks and other public amenities
    • iii) Colony improvement expenditure @ Rs. 6.00 per m²
    • iv) Engineer’s and Architect’s fee for surveying and planning the colony @ 4% on the sale of plots
    [7] (2067 Ashadh, Q.4(c))
    Solution
    Area to be acquired = 4,50,000 m²
    Sale price after development = Rs 40.00 per m²
    i) Establishment charges = 15% on the sale price
    ii) Area for roads, parks and public amenities = 35%
    iii) Colony improvement expenditure = Rs 6.00 per m²
    iv) Engineer's and architect's fee = 4% on the sale of plots

    Saleable area

    saleable area = 4,50,000 × (1 − 0.35) = 4,50,000 × 0.65 = 2,92,500 m²

    Sale price of the developed plots

    sale price = 2,92,500 × Rs 40 = Rs 1,17,00,000

    Deductions

    i) establishment charges @ 15% = 0.15 × 1,17,00,000 = Rs 17,55,000 ii) engineer's and architect's fee @ 4% = 0.04 × 1,17,00,000 = Rs 4,68,000 iii) colony improvement expenditure = 4,50,000 m² × Rs 6 = Rs 27,00,000 -------------- total deductions = Rs 49,23,000

    Maximum compensation

    compensation = 1,17,00,000 − 49,23,000 = Rs 67,77,000 rate per m² = 67,77,000 / 4,50,000 = Rs 15.06 per m²
    Maximum compensation payable to the land owners = Rs 67,77,000, i.e. Rs 15.06 per m².

    ENCE 351 §7.4.

  9. A building is situated in a town on a land measuring 600 m². The area of the built up portion is 20 m × 15 m. The building is provided with water supply, sanitary and electrical fittings and is of very sound construction and the life of which may be assumed as 100 yrs. Work out the valuation of the property, if the age of the building is 30 yrs. The prevailing plinth area rate is Rs. 15000.00 per m² and value of land is Rs. 500.00 per m². [10] (2067 Poush, Q.3(b))
    Solution
    Land = 600 m² @ Rs 500 per m²
    Built-up portion = 20 m × 15 m
    Building provided with water supply, sanitary and electrical fittings, of very sound construction
    Life = 100 years · present age = 30 years
    Prevailing plinth area rate = Rs 15,000 per m²
    Assumed: scrap value = 10% of the cost, straight line depreciation

    Replacement cost of the building by the plinth area method

    plinth area = 20 × 15 = 300 m² cost of building = 300 × Rs 15,000 = Rs 45,00,000

    Depreciation by the straight line method

    scrap value S = 10% of 45,00,000 = Rs 4,50,000 annual depreciation D = ( C − S ) / n = ( 45,00,000 − 4,50,000 ) / 100 = 40,50,000 / 100 = Rs 40,500 per year depreciation in 30 years = 40,500 × 30 = Rs 12,15,000

    Present value of the building

    = 45,00,000 − 12,15,000 = Rs 32,85,000

    Value of the land and total valuation

    land = 600 m² × Rs 500 = Rs 3,00,000 building = Rs 32,85,000 -------------- valuation of the property = Rs 35,85,000
    Valuation of the property = Rs 35,85,000 (building Rs 32,85,000 + land Rs 3,00,000).

    The plinth area rate of Rs 15,000/m² is stated to be for a building with water supply, sanitary and electrical fittings and of sound construction, so no further percentage is added for services. The building has used only 30 of its 100 years, so it retains 73% of its cost.

    ENCE 351 §7.4.

  10. A 4 storey building has just completed at a cost of Rs. 40,00,000. The building is constructed on a plot of 19 aana purchased for Rs. 25,00,000 in 2060. The prevailing rate of plots in the locality is Rs. 32,00,000 per ropani. Work out the standard rent per floor per month assuming the following outgoings:
    • i) Municipal tax 25% of ratable value
    • ii) Collection and management charge @ 3% of gross rent
    • iii) Repairs at 1% on 9/10th cost of construction
    • iv) Sinking fund @ 5% for 65 years on 90% cost of construction
    • v) Miscellaneous expenses @ Rs. 500 per month
    [10] (2066 Bhadra, Q.4(b))
    Solution
    4-storey building just completed at a cost of Rs 40,00,000
    Plot of 19 aana, purchased for Rs 25,00,000 in 2060
    Prevailing rate of plots = Rs 32,00,000 per ropani
    Outgoings: municipal tax 25% of ratable value · collection and management 3% of gross rent · repairs 1% on 9/10th cost of construction · sinking fund 5% for 65 years on 90% cost of construction · miscellaneous Rs 500 per month
    Assumed: expected net return on capital = 8%; ratable value taken as the gross annual rent

    Present value of the land

    1 ropani = 16 aana 19 aana = 19 / 16 = 1.1875 ropani value of land = 1.1875 × Rs 32,00,000 = Rs 38,00,000 ( the Rs 25,00,000 paid in 2060 is the historical COST and is not used )

    Total capital invested

    cost of building = Rs 40,00,000 present value of land = Rs 38,00,000 -------------- total capital = Rs 78,00,000

    Net return expected on the capital

    net return = 8% of 78,00,000 = Rs 6,24,000 per year

    Fixed annual outgoings

    repairs = 1% on 9/10th of the cost of construction = 0.01 × 0.90 × 40,00,000 = Rs 36,000.00 sinking fund on 90% of cost, 5%, 65 years (1.05)65 = 23.8399 S = 0.05 / ( 23.8399 − 1 ) = 0.0021892 annual SF = 0.90 × 40,00,000 × 0.0021892 = 36,00,000 × 0.0021892 = Rs 7,880.94 miscellaneous = 500 × 12 = Rs 6,000.00 -------------- total fixed outgoings = Rs 49,880.94

    Set up the rent equation

    Let R = gross annual rent. The outgoings that depend on R are: municipal tax = 25% of R collection and mgmt. = 3% of R gross rent − outgoings = net return R − 0.25R − 0.03R − 49,880.94 = 6,24,000 0.72 R = 6,24,000 + 49,880.94 = 6,73,880.94 R = 6,73,880.94 / 0.72 = Rs 9,35,945.76 per year

    Standard rent per floor per month

    number of floor-months in a year = 4 floors × 12 months = 48 rent per floor per month = 9,35,945.76 / 48 = Rs 19,498.87
    Standard rent = Rs 19,498.87 per floor per month, say Rs 19,500 per floor per month (gross annual rent Rs 9,35,946).

    Note two things. The land is taken at its present value (Rs 38,00,000 from the prevailing ropani rate), not at the Rs 25,00,000 paid in 2060 — standard rent must give a fair return on capital as it stands today. And the percentage outgoings are carried to the left side of the equation as fractions of the unknown R, which is why the answer comes out of a division by 0.72.

    A refinement worth knowing. The standard method takes a separate rate of return on the building and on the land — typically about 7% on the cost of construction and 6% on the cost of land, the land rate being the same as or a little less than the building rate. Working it that way here:
    net return = 0.07 × 40,00,000 + 0.06 × 38,00,000 = 2,80,000 + 2,28,000 = Rs 5,08,000, giving R = (5,08,000 + 49,880.94)/0.72 = Rs 7,74,834 a year, or about Rs 16,142 per floor per month. Either treatment is accepted provided the assumed rate or rates are stated.

    ENCE 351 §7.4; the standard-rent equation follows Chakraborti, Estimating, Costing and Specification, §15-12 (standard rent = net return + outgoings).

  11. A 4 story building having a cubic content of 400 m³ was constructed 25 yrs ago on a freehold land measuring 500 m². The building fetches a rent of Rs. 25,000.00 per month. What amount will you recommend for advancing a loan to the owner against mortgage if the rate of land in that area is Rs. 2000.00 per m²? Assume the following outgoings:
    • i) Municipal and property taxes @ 30% of gross rent
    • ii) Collection and management charges @ 3% of the gross rent
    • iii) Repairs and maintenance @ 8% of gross rent Assume the future life to be 65 yrs, rate of interest as 8% and for redemption of capital 4%.
    [10] (2065 Shrawan, Q.4(b))
    Solution
    4-storey building, cubic content 400 m³, constructed 25 years ago
    Freehold land 500 m² @ Rs 2,000 per m²
    Rent = Rs 25,000 per month
    Outgoings: municipal and property taxes 30% of gross rent · collection and management 3% · repairs and maintenance 8%
    Future life = 65 years · rate of interest = 8% · redemption of capital = 4%

    Net annual income

    gross annual rent = 25,000 × 12 = Rs 3,00,000 outgoings : municipal and property taxes 30% = Rs 90,000 collection and management 3% = Rs 9,000 repairs and maintenance 8% = Rs 24,000 ---- 41% = Rs 1,23,000 net annual income = 3,00,000 − 1,23,000 = Rs 1,77,000

    Year's purchase — 65 years, 8% interest, 4% redemption

    (1.04)65 = 12.7987 S = 0.04 / ( 12.7987 − 1 ) = 0.04 / 11.7987 = 0.0033902 YP = 1 / ( i + S ) = 1 / ( 0.08 + 0.0033902 ) = 1 / 0.0833902 = 11.9918

    Value of the property

    capitalized value of building = 1,77,000 × 11.9918 = Rs 21,22,551.73 value of land = 500 × 2,000 = Rs 10,00,000.00 ---------------- total value of the property = Rs 31,22,551.73

    Loan that may be advanced against the mortgage

    A lender does not advance the full value; a margin is kept against fall in price and cost of recovery. Banks normally advance about two-thirds of the valuated amount. loan = (2/3) × 31,22,551.73 = Rs 20,81,701.15 ( at 80% it would be Rs 24,98,041.38 )
    Value of the property = Rs 31,22,551.73. The amount recommended for advancing as a loan against mortgage ≈ Rs 20,81,700 (two-thirds of the valuation).

    State the margin you adopt and why. The cubic content of 400 m³ and the age of 25 years are given as background — the valuation here is by the rental (capitalization) method, which uses the income and the remaining life, so the cube content is not needed.

    ENCE 351 §7.4.

  12. An office building having a plinth area of 5000 sq. ft. was constructed at the cost of Rs. 4,000.00 per sq. ft. The building is two storey RCC structure on a 6 aana plot. The Government rate of land is Rs. 10,00,000 per aana and commercial rate of land is 40,00,000 per aana. The office building is given on a monthly rental of Rs. 50,000. Life of the structure may be taken as 70 years. Calculate maximum loan that can be sanctioned from a bank which provides loan amount equivalent to 40% of valuated amount. The bank policy for land valuation is to take 70% of commercial rate and 30% of government rate. The annual expenses of the building are 30% of gross income, prevailing interest rate is 10% and rate of capital redemption is 5%. [6] (CM 2081 Chaitra, Q.8)
    Solution
    Office building, plinth area 5,000 sq ft, built at Rs 4,000 per sq ft
    Two-storey RCC structure on a 6 aana plot
    Government rate of land = Rs 10,00,000 per aana
    Commercial rate of land = Rs 40,00,000 per aana
    Bank policy for land: 70% of commercial + 30% of government rate
    Monthly rental = Rs 50,000 · life of structure = 70 years
    Annual expenses = 30% of gross income · interest 10% · capital redemption 5%
    Bank sanctions a loan of 40% of the valuated amount

    Value of the land by the bank's policy

    rate adopted per aana = 0.70 × 40,00,000 + 0.30 × 10,00,000 = 28,00,000 + 3,00,000 = Rs 31,00,000 per aana value of land = 6 aana × 31,00,000 = Rs 1,86,00,000

    Value of the building by the plinth area method

    value of building = 5,000 sq ft × Rs 4,000 = Rs 2,00,00,000 ( the building is newly constructed, so no depreciation is deducted )

    Total valuation of the property

    land = Rs 1,86,00,000 building = Rs 2,00,00,000 --------------- total valuated amount = Rs 3,86,00,000

    Maximum loan that can be sanctioned

    loan = 40% of the valuated amount = 0.40 × 3,86,00,000 = Rs 1,54,40,000
    Total valuation of the property = Rs 3,86,00,000; maximum loan that the bank can sanction = Rs 1,54,40,000 (Rs 1.544 crore).

    Cross-check by the rental (income) method

    gross annual income = 50,000 × 12 = Rs 6,00,000 annual expenses = 30% = Rs 1,80,000 net annual income = Rs 4,20,000 YP : (1.05)70 = 30.4264 S = 0.05 / ( 30.4264 − 1 ) = 0.0016992 YP = 1 / ( 0.10 + 0.0016992 ) = 9.8329 capitalized value = 4,20,000 × 9.8329 = Rs 41,29,828

    The income method gives only about Rs 41 lakh — far below the cost-based figure of Rs 3.86 crore. That is not an error: it shows that the building is let at a rent well below a fair return on its capital value (Rs 6 lakh a year on Rs 3.86 crore is barely 1.6%). For mortgage purposes the bank's own cost-based policy governs, which is why the loan is computed on Rs 3,86,00,000. A valuer should report both figures and explain the gap.

    ENCE 351 §7.4.

  13. A freehold property consisting of RCC building having a total area of 500 m² constructed 10 years ago is proposed to be purchased by Mr. Thapa. The present market rate of construction for similar type of building is Rs. 45,000/m². The total area of land is 500 m². The commercial market rate (CMR) of this land is Rs. 1,00,000/m². The government registration rate (GRR) for this land is Rs. 30,000/m². Use 60:40 proportion for determining cost of land. Assume life of building to be 70 years and scrap value as 10%. Advise Mr. Thapa as to what cost he should purchase the property. Use Plinth area method of valuation and straight line method of depreciation. [6] (CM 2080 Chaitra, Q.12)
    Solution
    RCC building, total area 500 m², constructed 10 years ago
    Present market rate of construction = Rs 45,000 per m²
    Total area of land = 500 m²
    Commercial market rate (CMR) = Rs 1,00,000 per m²
    Government registration rate (GRR) = Rs 30,000 per m²
    Use 60 : 40 proportion of CMR : GRR for the cost of land
    Life of building = 70 years · scrap value = 10%
    Plinth area method of valuation, straight line method of depreciation

    Value of the land

    rate adopted = 0.60 × CMR + 0.40 × GRR = 0.60 × 1,00,000 + 0.40 × 30,000 = 60,000 + 12,000 = Rs 72,000 per m² value of land = 500 × 72,000 = Rs 3,60,00,000

    Replacement cost of the building — plinth area method

    cost = 500 m² × Rs 45,000 = Rs 2,25,00,000

    Depreciation — straight line method

    scrap value S = 10% of 2,25,00,000 = Rs 22,50,000 annual depreciation D = ( C − S ) / n = ( 2,25,00,000 − 22,50,000 ) / 70 = 2,02,50,000 / 70 = Rs 2,89,285.71 per year depreciation in 10 years = 2,89,285.71 × 10 = Rs 28,92,857.14

    Depreciated value of the building

    = 2,25,00,000 − 28,92,857.14 = Rs 1,96,07,142.86

    Total value of the property

    land = Rs 3,60,00,000.00 building (depreciated) = Rs 1,96,07,142.86 ------------------ value of the property = Rs 5,56,07,142.86
    Advice to Mr. Thapa: the property is worth Rs 5,56,07,143 (say Rs 5.56 crore) — land Rs 3.60 crore plus building Rs 1.96 crore. He should not pay more than this.

    The building has used 10 of its 70 years, so it has lost 12.86% of its depreciable value and retains about 87% of its replacement cost. Note that the land, which does not depreciate, is 65% of the total — the older the building, the more the land dominates.

    ENCE 351 §7.4.

  14. A building having a cubic of 1600 m³ was constructed 14 years ago on a free hold land measuring 900 m². The building fetched a rent of Rs. 12300 per month. What amount will you recommend for advancing a loan on a property against the Mortgage, if the rate of land in that area is Rs. 800 per sq. meter? The building has following expenditure headings:
    • Insurance premium Rs. 6700 per annum
    • Repair and maintenance 7% of gross rent
    • Taxes 27% of gross rent
    • Management collection charges 5% of gross rent
    [7] (CM 2079 Chaitra, Q.13)
    Solution
    Building of cubic content 1,600 m³, constructed 14 years ago
    Freehold land 900 m² @ Rs 800 per m²
    Rent = Rs 12,300 per month
    Insurance premium = Rs 6,700 per annum
    Repair and maintenance = 7% of gross rent · taxes = 27% · management and collection = 5%
    Assumed (not stated in the question): total life 80 years, hence future life 66 years; interest on capital 8%; redemption of capital 4%

    Net annual income

    gross annual rent = 12,300 × 12 = Rs 1,47,600.00 outgoings : repair and maintenance 7% = Rs 10,332.00 taxes 27% = Rs 39,852.00 management and collection 5% = Rs 7,380.00 ---- 39% of gross = Rs 57,564.00 insurance premium = Rs 6,700.00 -------------- total outgoings = Rs 64,264.00 net annual income = 1,47,600 − 64,264 = Rs 83,336.00

    Year's purchase — 66 years, 8% interest, 4% redemption

    (1.04)66 = 13.3106 S = 0.04 / ( 13.3106 − 1 ) = 0.04 / 12.3106 = 0.0032493 YP = 1 / ( 0.08 + 0.0032493 ) = 1 / 0.0832493 = 12.0121

    Value of the property

    capitalized value of building = 83,336 × 12.0121 = Rs 10,01,042.53 value of land = 900 × 800 = Rs 7,20,000.00 ---------------- total value of the property = Rs 17,21,042.53

    Loan recommended against the mortgage

    banks normally advance about two-thirds of the valuation, keeping a margin against fall in price and cost of recovery: loan = (2/3) × 17,21,042.53 = Rs 11,47,361.69
    Value of the property = Rs 17,21,042.53; the amount recommended for advancing as a loan against the mortgage ≈ Rs 11,47,400 (two-thirds of the valuation).

    The rate of interest, the redemption rate and the total life are not given in this question, so they must be assumed and the assumption stated. The cubic content of 1,600 m³ would be used if the building were valued by the cube rate method; here the rental method is used, so it is not needed.

    ENCE 351 §7.4.

  15. Calculate the value of a building built 20 years ago having plinth area 500 sqm, constructed in the land of 1000 sqm. Current market value of the land is Rs. 25,000 per sqm and rate of building is Rs. 50,000 per sqm. Assume suitable data if necessary. [6] (CM 2075 Bhadra, Q.6(b))
    Solution
    Building built 20 years ago, plinth area 500 m²
    Land area 1,000 m², current market value Rs 25,000 per m²
    Rate of building = Rs 50,000 per m²
    Assumed: life of the building 70 years, scrap value 10%, straight line depreciation

    Value of the land

    land = 1,000 m² × Rs 25,000 = Rs 2,50,00,000

    Replacement cost of the building

    cost = 500 m² × Rs 50,000 = Rs 2,50,00,000

    Depreciation — straight line method

    scrap value S = 10% of 2,50,00,000 = Rs 25,00,000 D = ( C − S ) / n = ( 2,50,00,000 − 25,00,000 ) / 70 = 2,25,00,000 / 70 = Rs 3,21,428.57 per year depreciation in 20 years = 3,21,428.57 × 20 = Rs 64,28,571.43

    Present value of the building and of the property

    depreciated value of building = 2,50,00,000 − 64,28,571.43 = Rs 1,85,71,428.57 value of land = Rs 2,50,00,000.00 ------------------ value of the property = Rs 4,35,71,428.57
    Value of the property = Rs 4,35,71,429, say Rs 4.36 crore (land Rs 2.50 crore + building Rs 1.86 crore).

    The question says "assume suitable data if necessary". The life and the scrap value must be assumed, and the assumption must be stated — a life of 60 years instead of 70 would give a depreciation of Rs 75,00,000 and a property value of Rs 4.25 crore. Marks are given for stating the assumption, not for a particular number.

    ENCE 351 §7.4.

  16. Calculate the value of a building built 10 years ago having a plinth area of 450 sqm, constructed in the land of 1000 sqm. Current market value of land is Rs. 15,000 per sqm and rate of building is Rs. 30,000 per sqm. Assume suitable data if necessary. [8] (CM 2071 Bhadra, Q.13)
    Solution
    Building built 10 years ago, plinth area 450 m²
    Land area 1,000 m², current market value Rs 15,000 per m²
    Rate of building = Rs 30,000 per m²
    Assumed: life of the building 70 years, scrap value 10%, straight line depreciation

    Value of the land

    land = 1,000 m² × Rs 15,000 = Rs 1,50,00,000

    Replacement cost of the building

    cost = 450 m² × Rs 30,000 = Rs 1,35,00,000

    Depreciation — straight line method

    scrap value S = 10% of 1,35,00,000 = Rs 13,50,000 D = ( C − S ) / n = ( 1,35,00,000 − 13,50,000 ) / 70 = 1,21,50,000 / 70 = Rs 1,73,571.43 per year depreciation in 10 years = 1,73,571.43 × 10 = Rs 17,35,714.29

    Present value of the building and of the property

    depreciated value of building = 1,35,00,000 − 17,35,714.29 = Rs 1,17,64,285.71 value of land = Rs 1,50,00,000.00 ------------------ value of the property = Rs 2,67,64,285.71
    Value of the property = Rs 2,67,64,286, say Rs 2.68 crore (land Rs 1.50 crore + building Rs 1.18 crore).

    State every assumed figure. The building has used only 10 of its 70 years and so retains about 87% of its replacement cost.

    ENCE 351 §7.4.

Methods of valuation

  1. Rental method (capitalization of net rent). The net annual rental income is found by deducting outgoings from the gross rent, and multiplied by the year's purchase. Suitable where reliable rents exist and rent control does not distort them.
    capitalized value = net annual income × YP
  2. Direct comparison with the capital value. The property is compared with recent sales of similar properties nearby, with adjustments for differences in size, frontage, age and condition. The usual method for land.
  3. Valuation based on profit. The net profit the property generates is capitalized. Used for commercial properties whose value derives from the business — hotels, cinemas, restaurants, petrol pumps.
  4. Valuation based on cost (cost method). The actual cost of construction is worked out and depreciation deducted for age and condition. The usual method for a building, and the one used for insurance.
    value = replacement cost − depreciation ( + present value of the land )
  5. Development method. The value of land with development potential is found from the value of the finished scheme less the cost of developing it. Used for large plots ripe for building, and for a building to be converted.
  6. Depreciation method of valuation. The building is divided into four parts — walls, roof, floors and finishings — and each is depreciated according to its own life and condition before the values are added.

Valuation of land

Development method — maximum compensation for land acquired

This is the standard numerical form of the development method. The developer works backwards: what the finished plots will fetch, less everything he must spend to make them, is the most he can afford to pay for the raw land.

Example. A builder must acquire 4,00,000 m² for a colony. After development the plots will sell at Rs 120 per m². Find the maximum compensation payable to the present owners, given that 35% of the area must be given up to roads, parks and open space; establishment charges are 15% of the sale price; colony improvement costs Rs 15 per m²; and the engineer's and architect's fees are 4% of the sale price.

roads, parks, open space = 0.35 × 4,00,000 = 1,40,000 m² saleable area = 4,00,000 − 1,40,000 = 2,60,000 m² gross income = 2,60,000 × 120 = Rs 3,12,00,000

Against that gross income stand the outgoings:

establishment 15% × 3,12,00,000 = Rs 46,80,000 colony improvement 4,00,000 × 15 = Rs 60,00,000 engineer, architect 4% × 3,12,00,000 = Rs 12,48,000 ---------------- total outgoings = Rs 1,19,28,000
value of the raw land = 3,12,00,000 − 1,19,28,000 = Rs 1,92,72,000 maximum compensation = 1,92,72,000 / 4,00,000 = Rs 48.18 per m²

Two different areas are in play, and that is where the marks go. The income is earned only by the 2,60,000 m² that can actually be sold, but the colony improvement expense and the final division are over the whole 4,00,000 m² — the owners must be paid for every square metre taken from them, including the land that becomes road. Dividing by 2,60,000 gives Rs 74.12 and is the usual mistake.

Which method to use

PropertyUsual method
Open landDirect comparison; belting for deep plots
Residential buildingCost method (replacement less depreciation) plus land value
Rented / tenanted propertyRental method — capitalization of net income
Hotel, cinema, petrol pumpProfit-based method
Land ripe for developmentDevelopment method
Insurance claimCost method — replacement value less depreciation

Fixation of rent

The rent of a building is fixed as a percentage of annual interest on the capital cost, plus all the annual outgoings:

gross rent = net return on capital + outgoings net return = ( interest rate ) × ( capital cost ) rent per month = gross annual rent / 12

The capital cost for this purpose is not just the bare building. It includes:

  1. the cost of construction of the building;
  2. the cost of the sanitary and water supply work;
  3. the cost of the electrical installation;
  4. the cost of any subsequent additions and alterations; and
  5. the cost of raising, levelling and dressing the site, the compound wall, fences and gates, storm water drains, and the approach and internal roads.

Two figures worth remembering. The owner normally expects about 2% more than the prevailing rate of interest, to cover the risk on his investment — so if the market rate is 10%, he looks for about 12%. And while 12% may be reasonable for a private investment in a building, government allows only about 6% on its own housing loans.

The rent found this way is the standard rent. The rent actually obtainable may be higher or lower, depending on the situation of the property, the type of construction, and demand and supply.

Easement

An easement is a right that the owner of one property enjoys over the property of another. It is an encumbrance on the servient property and reduces its value. Common easement rights are the right of way, the right to light and air, the right of flow of rain water over another's land, and the right of support for a building from the adjoining owner's land.

An easement right may be created by a document, or acquired by continuous and uninterrupted enjoyment for 20 years. A valuer must search for easements, because an unrecorded right of way across a plot can cut its value sharply.

Pandey & Katwal, Complete Manual §7.5–7.6; fixation of rent, the composition of the capital cost, the 2% risk premium and the law of easement follow B. N. Dutta, Estimating and Costing in Civil Engineering, book pp.632–634.

7.5 Valuation report and its components20672066

Past Exam Questions on this Topic

  1. Mention the various data you will need to collect as a valuator for land valuation. [4] (2067 Ashadh, Q.4(b))
    Solution

    Data to be collected by a valuer for the valuation of land

    1. Legal / title data

    • Certificate of ownership (lalpurja) and the name of the registered owner.
    • Plot number, sheet number, ward, municipality and district.
    • Tenure — freehold or leasehold, and the unexpired period of the lease.
    • Encumbrances — mortgage, lien, court case, tenancy, right of way, easement; a search of the land revenue office record.
    • Land revenue and tax paid, and any arrears.

    2. Physical data

    • Area, shape, dimensions and frontage; the cadastral (napi) map and a site plan.
    • Levels and topography, filling or cutting required, liability to flood or landslide.
    • Soil condition and bearing capacity.
    • Access — width and type of the approach road, and whether it is public.
    • Availability of water supply, drainage, sewer, electricity and telephone.
    • Existing structures, trees and crops on the land.

    3. Planning data

    • Land use zoning, and any restriction on the use.
    • Setback (right of way) requirement, ground coverage, floor area ratio and height limit under the municipal by-laws.
    • Any proposed road widening, acquisition or public work affecting the plot.

    4. Market data

    • The government registration rate (minimum valuation rate) of the locality.
    • The prevailing commercial market rate, from recent registered sale deeds of comparable plots nearby.
    • Rent obtainable, and the trend of prices in the locality.
    • Development in the neighbourhood, and its effect on demand.

    ENCE 351 §7.5.

  2. You have been asked to prepare a valuation report of land for a security of loan. Describe various data which you will collect as a valuation. [5] (2066 Bhadra, Q.4(a))
    Solution

    A valuation report prepared as security for a loan is relied upon by the lender, so the valuer must be able to defend every figure in it. The data to be collected are:

    Data to be collected by a valuer for the valuation of land

    1. Legal / title data

    • Certificate of ownership (lalpurja) and the name of the registered owner.
    • Plot number, sheet number, ward, municipality and district.
    • Tenure — freehold or leasehold, and the unexpired period of the lease.
    • Encumbrances — mortgage, lien, court case, tenancy, right of way, easement; a search of the land revenue office record.
    • Land revenue and tax paid, and any arrears.

    2. Physical data

    • Area, shape, dimensions and frontage; the cadastral (napi) map and a site plan.
    • Levels and topography, filling or cutting required, liability to flood or landslide.
    • Soil condition and bearing capacity.
    • Access — width and type of the approach road, and whether it is public.
    • Availability of water supply, drainage, sewer, electricity and telephone.
    • Existing structures, trees and crops on the land.

    3. Planning data

    • Land use zoning, and any restriction on the use.
    • Setback (right of way) requirement, ground coverage, floor area ratio and height limit under the municipal by-laws.
    • Any proposed road widening, acquisition or public work affecting the plot.

    4. Market data

    • The government registration rate (minimum valuation rate) of the locality.
    • The prevailing commercial market rate, from recent registered sale deeds of comparable plots nearby.
    • Rent obtainable, and the trend of prices in the locality.
    • Development in the neighbourhood, and its effect on demand.

    5. Data on the building, if any, standing on the land

    • Type of structure, number of storeys, plinth area of each floor.
    • Specification and quality of construction, and the plinth area rate of a comparable recent building.
    • Age of the building, its present condition, and its remaining useful life.
    • Approved drawings and the municipal building permit.
    • Rent actually received, and the outgoings.

    Components of a valuation report

    1. Title and reference — who ordered the valuation, and for what purpose (sale, loan, tax, acquisition).
    2. Particulars of the property — owner, plot number, area, location, boundaries.
    3. Title and tenure — ownership documents examined, tenure, and any encumbrance.
    4. Description of the land — shape, frontage, levels, access, services.
    5. Description of the building — type, storeys, plinth area, specification, age, present condition, remaining life.
    6. Date of inspection and the date to which the valuation relates.
    7. Method of valuation adopted, with the reason for choosing it.
    8. Detailed calculations — rates adopted and their source, depreciation, outgoings, year's purchase.
    9. Value arrived at — land, building and total, in figures and in words.
    10. Assumptions, limitations and remarks.
    11. Enclosures — site plan, cadastral map, photographs, copies of the ownership certificate and tax receipts.
    12. Declaration, signature, name, registration number and date of the valuer.

    For a mortgage valuation the valuer must be especially careful on three points: the title must be clear and marketable, the property must be free of encumbrances, and a margin must be kept — a bank normally advances only about two-thirds of the valuated amount, so that it is protected against a fall in price and the cost of recovery.

    ENCE 351 §7.5.

A valuation report is the valuer's signed statement of the value of a property, with the reasoning that supports it. It has to stand up in a bank, a tax office or a court, so its form is fairly standard.

Components of a valuation report

  1. Introduction — who instructed the valuation, the purpose for which it is made, and the date of valuation.
  2. Identification of the property — owner's name, plot / kitta number, ward, municipality or VDC, district, and boundaries on all four sides.
  3. Legal particulars — title deed, tenure, encumbrances, tenancy, litigation.
  4. Description of the land — area, shape, frontage, level, approach road and its width, land use permitted.
  5. Description of the building — year of construction, number of storeys, plinth area of each floor, structural system, specification of foundation, walls, roof, floors, doors and windows, finishes, and the services provided.
  6. Present condition and the estimated remaining life; observed defects.
  7. Method of valuation adopted, with reasons, and the rates assumed with their source.
  8. Detailed calculation — land value, replacement cost of the building, depreciation, and the value of any other improvements (boundary wall, gate, well, landscaping).
  9. Summary of value and the valuer's opinion of the fair market value, in figures and in words.
  10. Declaration and signature of the valuer with registration number.
  11. Annexures — site plan, floor plans, photographs, copy of the title deed and of the approved drawing.

The valuation must state clearly that it is valid as on a particular date and for a particular purpose. A valuation made for a bank mortgage cannot be reused for an insurance claim.

Pandey & Katwal, Complete Manual §7.7; format per the standard Nepalese bank valuation proforma.

Sources consulted for this chapter

These are the references actually used in writing this chapter. Where a worked example is taken from one of them, the figure or the sheet is recomputed here from the stated dimensions rather than transcribed.