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Quick Revision

Formula and Constant Sheet

9 sections all eight chapters Estimating and Costing (ENCE 351)

Everything on this page is taken from the chapter notes — nothing new is introduced. Use it the night before the paper; follow a link back to the chapter whenever a line needs its derivation.

1Units and modes of measurement

ItemUnitItemUnit
Earthwork, concrete, brickworkm³Plastering, pointing, paintingm²
Stone masonry, well steiningm³Damp proof coursem²
Reinforcement steelkg (or quintal)Honeycomb brickworkm²
Iron grills, gratingskgShuttering, formworkm²
RC sunshade (chajja)running mDoors and windows with framem²
Cornice, skirting, railingrunning mWood work in beams, postsm³
Pipes, kerbs, edgingrunning mWhite washing, distemperingm²

2Deduction rules

WhereRule
Brickwork — openingsDeduct openings over 0.1 m² (1000 cm²). Smaller ones are ignored.
Brickwork — bearingsBearings of lintels, beams and posts up to 500 cm² (0.05 m²) in section are not deducted. A section is an area, not a volume.
Brickwork — plates and chajjaBed plates, wall plates and chajja bearings up to 10 cm depth are not deducted.
Brickwork — slab bearingThe bearing of an RCC slab on a wall is never deducted.
PlasteringOpening up to 0.5 m² — no deduction. 0.5 to 3 m² — deduct one face. Over 3 m² — deduct both faces, but add the jambs and soffit.
ConcreteDeduct openings and embedded steel only when they exceed the same limits; reinforcement volume is never deducted from concrete.

3Taking out quantities

Three ways to reach the same quantity. The centre-line method is fastest, the long wall – short wall method is the safest when walls differ in thickness.

MethodLength used
Long wall – short wallLong wall = centre-to-centre length + one width (out to out). Short wall = centre-to-centre length − one width (in to in).
Centre lineOne total centre-line length for the whole building, then − ½ × width of that item × number of junctions.
Crossing / bayUsed for repetitive framed bays; take one bay and multiply.

A junction is where THREE walls meet — a plain closed rectangle has none, and a single partition creates two. The centre-line length is not found once and reused: the deduction is half the width of each item, so a 70 cm footing, a 50 cm wall and a 30 cm wall all give different lengths. In the long wall – short wall method a partition counts as a short wall.

4Types of estimate and the standard percentages

QuantityValue
Contingencies3 to 5% of the estimated cost
Work-charged establishment1.5 to 2%
Departmental charges10 to 15%
Revised estimate needed whencost exceeds the sanctioned amount by more than 5%
Benefit–cost ratioannual benefit ÷ annual O&M cost; must exceed 1
Contingency and establishmentcomputed on every sub-head except land
Work valuescheduled items only — excludes contingency, establishment and tools & plant; it is the amount put to tender

5Earthwork and road formulas

For a section of formation width B, depth D and side slope s horizontal to 1 vertical, on level ground:

area of one section A = B·D + s·D² mid-sectional volume V = L × ( B·Dᵤ + s·Dᵤ² ) Dᵤ = mean DEPTH (under-estimates) mean-sectional volume V = L × (A₁ + A₂)/2 mean of the AREAS (over-estimates) prismoidal volume V = (L/6)(A₁ + 4Aₖ + A₂) most accurate, lies between the two

That bracketing is the answer to “compare the three methods”: the prismoidal value always falls between the mid-sectional and the mean-sectional value.

On side-lying (hill) ground with cross slope 1 in r and side slope 1 in s, taking b = B/2:

s·b² + r²( 2b·d + s·d² ) A = -------------------------------- r² − s²

The s·b² term is the one that is usually dropped; leaving it out makes the area about 2% low.

Zero (balance) point — where cutting changes to filling, at distance x from the section of depth d when the next section at distance L has height h:

x = L · d / ( d + h ) mean cross slope at that point r₀ = 2 r₁ r₂ / ( r₁ + r₂ ) ( harmonic mean ) mean formation width b₀ = ( B₁ + B₂ ) / 2

Slopes are rates, so they average harmonically, not arithmetically. Widths are lengths and average arithmetically.

Canal lining — measured on the wetted perimeter:

P = B + 2D√(1 + s²)

6Material constants

QuantityValue
Bricks in brickwork500 per m³ (modular 190×90×90, 200×100×100 with mortar)
Brick flat soling50 bricks per m²
Mortar in brickworkabout 23% of the volume of masonry
Mortar in rubble stone masonryabout 32%
Cement bag50 kg ÷ 1440 kg/m³ = 0.0347 m³, so 28.8 bags per m³
Dry volume factor — concrete1.54 (Nepali practice: wet + 50 to 55%)
Dry volume factor — mortar, plaster1.30 (wet + 30 to 35%)
PCC 1:3:6 with brick ballastdry factor 1.60
Water cement ratio0.50 for concrete, 0.80 for plaster; specifications cap mixing water at 30 litres per bag
Floor concreteadd 10% for unevenness of the base before the dry-volume factor
Steel unit weightw = d²/162 kg per metre

Cement, sand and aggregate for 1 m³ of finished concrete:

MixCementSandAggregate
1 : 1.5 : 38.064 bags0.42 m³0.84 m³
1 : 2 : 46.336 bags0.44 m³0.88 m³

Both rows are just 1.54 ÷ (sum of proportions), shared out. For 1:2:4 the sum is 7, so cement = 1.54/7 = 0.22 m³ = 0.22 × 28.8 = 6.336 bags, sand = 2 × 0.22 = 0.44 and aggregate = 4 × 0.22 = 0.88. Learn the method, not the table.

Materials from a finished quantity — the standard 5-mark question:

number of bricks = volume of masonry ÷ volume of ONE brick WITH mortar volume of mortar = volume of masonry − volume of the bricks WITHOUT mortar dry mortar = wet mortar × 1.30 cement = dry mortar × ( 1 / sum of proportions ) sand = dry mortar × ( parts of sand / sum of proportions )

Two checks before you write the answer: bricks should come to about 500 per m³, and mortar to about 20 to 25% of the masonry. If your figures fall far outside those, look for an arithmetic slip.

7Analysis of rates

The analysed rate is built in four heads and quoted excluding VAT:

A materials (quantity × rate, carriage included) B labour (mason, unskilled, bhisti) C hire of tools and plant, and water charge D overhead and profit = 15% of ( A + B + C ) ------------------------ rate per unit = A + B + C + D

The water charge is 1% of (materials + labour). Of the 15%, roughly 10% is profit. 13% VAT is added later, in the summary of cost, not in the analysed rate. No profit is allowed on departmentally supplied materials, but their carriage from the godown is added. Cement carriage is computed on weight in kg, not on the number of bags.

8Valuation and depreciation

C = original cost, S = scrap or salvage value, n = life in years, i = rate of interest as a decimal, m = present age.

straight line annual depreciation D = ( C − S ) / n constant percentage p = 1 − ( S / C )^(1/n) value after m years = C(1 − p)^m sinking fund annual instalment I = ( C − S ) · i / [ (1+i)ⁿ − 1 ]

Total depreciation when the building is m years into an n year life:

(1 + i)ᵐ − 1 D = C × ---------------- (1 + i)ⁿ − 1

Do this as one division. The tabulated sinking fund coefficient is tiny (of the order of 0.0000488 for 80 years at 10%), and rounding it to three significant figures moves the answer by more than 1%. Check the formula by putting m = n: it must give D = C.

TermMeaning
Year's purchase (YP)the number of years' net income that equals the capital value; for a perpetual income YP = 1 / i = 100 ÷ rate per cent
Capitalised valuenet annual income × YP
Scrap valuevalue of the material alone when dismantled, about 10% of cost
Salvage valuevalue at the end of the useful life, sold without being broken up
Obsolescenceloss of value from a change in design, fashion or use; there is no method of calculating it
Standard rentnet return + outgoings; about 7% on the building and 6% on the land
Easementacquired by 20 years of uninterrupted enjoyment
Landnever depreciates — it usually dominates the value of an old property
Nepali land unit1 ropani = 16 aana

Development method — the most a builder can pay for raw land:

value of raw land = ( income from the SALEABLE area ) − ( all development outgoings ) compensation per m² = value of raw land ÷ the WHOLE area acquired

Two different areas: the income comes only from what can be sold, but the improvement cost and the final division are over the whole area taken — the owners are paid for the land that becomes road as well.

9Checks worth doing before you hand in

CheckExpected range
Steel in RCC80 to 120 kg per m³ of concrete, or 4 to 6 kg per m² of built-up area
Bricks500 per m³ of brickwork
Mortar20 to 25% of the volume of masonry
Lintel lengthclear span + 2 bearings; bearing = thickness of the lintel, minimum 12 cm
Beam in a framed buildingmeasure the depth below the slab (500 − 125 = 375 mm), or the flange is counted twice
Septic tank proportionslength : width from 3:1 to 6:1, width 0.75 to 1.8 m, liquid depth 0.9 to 2.1 m
Manhole cover0.45 × 0.45 = 0.2025 m² — over 0.1 m², so it is deducted